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slega [8]
4 years ago
5

Find the volume of the hemisphere shown. remember a hemisphere is half of a sphere. r = 5

Mathematics
1 answer:
jenyasd209 [6]4 years ago
3 0
As we know from geometry, the volume of any given sphere is

V = 4/3*πr³

Since a hemisphere is half of any given sphere, its volume should be

V = 4/3*πr³ ÷ 2
V = 2/3*πr³

This will be our working equation for finding the volume of hemisphere. Since r is already given to be 5 units, we substitute this to the working equation:

V = 2/3*π(5)³
V = 261.8 cubic units
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Which transformations will produce similar, but not congruent, figures?
Elena-2011 [213]
The answer is D or <span>Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V" . I just took the test and I hope I helped : )</span>
3 0
3 years ago
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Given the following diagram, find the missing measure. G
jonny [76]

The Given Triangle PMO is a Right Angled Triangle with m∠M = 90°

Given m∠P = 40°

We know that : Sum of Angles in a Triangle = 180°

⇒ m∠P + m∠M  + m∠O = 180°

⇒ 40° + 90° + m∠O = 180°

⇒ 130° + m∠O = 180°

⇒ m∠O = 180° - 130°

⇒ m∠O = 50°

We can notice that m∠O and m∠1 form a Linear Pair (180°)

⇒ m∠O + m∠1 = 180°

⇒ 50° + m∠1 = 180°

⇒ m∠1 = 180° - 50°

⇒ m∠1 = 130°

Last Option is the Answer

6 0
3 years ago
Identifying slope and y intercept of a line
Oxana [17]

y = 1 - 3x goes to slope -3, y-intercept at 1

x - 3 = y goes to slope 1, y-intercept at -3

y = 3x - 1 goes to slope 3, y-intercept at -1

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7 0
2 years ago
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Which expression is equivalent to 2n+n-0.65n<br><br>3n-0.65<br>3n - 0.35<br>2.65n<br>2.35n​
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8 0
3 years ago
An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If t
pshichka [43]

Answer:

\theta = n\pi

where n = ..., -2,-1,0,1,2...

Step-by-step explanation:

given equation is:

\cos{2\theta} - 1 = 0

since no range is provided we can solve for all values of \theta:

\cos{2\theta} = 1

2\theta = \cos^{-1}{(1)}

2\theta = 0, 2\pi for one cycle of cos (0 \leq \theta \leq 2\pi)

2\theta = 0, 2\pi, 4\pi, 6\pi ... 2n\pi for all cycles of cos

we should also include negative values.

2\theta = -4\pi,-2\pi,0, 2\pi, 4\pi,... 2n\pi

we can divide each value by 2, to get the solutions for \theta instead of 2\theta

Answer:

\theta = -2\pi,-\pi,0, \pi, 2\pi,... n\pi

This is the solution of the equation \cos{2\theta} - 1 = 0.

In its most general form we can write all solutions of the equation in terms of n

\theta = n\pi where n = ..., -2,-1,0,1,2... or n is an integer.

4 0
3 years ago
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