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salantis [7]
3 years ago
10

Line CD is tangent to circle A at point B. Segment AB is a radius of circle A. What can be concluded about angle ABD?

Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0
<span>Segment AB is a radius of circle A. We can conclude that angle ABD is complementary to angle ABC. The answer is letter C. Complementary angles are angles that forms 90 degrees. Since the l</span>ine CD is tangent to circle A at point B and the distance of line CB is the same as that in line BD then it forms a perpendicular line at point B which divides both angle in 90 degrees.
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PlS help lots of points
Len [333]
I feel like there is something missing from this question, for example how large is the tree house? If these are just plain measurements, then I would opt for B.

3 0
2 years ago
Suppose in a certain state, 60% of the people have a Visa credit card, 40% have a MasterCard, and 24% have both. Let V be the ev
REY [17]

Answer:

The question has some details missing; i.e

a. What is the probability that the shopper has neither type of card?

b. What is the probability that the shopper has both types of card?

c. What is the probability the individual has a Visa card but not a Mastercard? (Hint: You will use the answer)

a) 0.24

b) 0.24

c) 0.36

Step-by-step explanation:

The detailed steps is shown in the attachment.

3 0
3 years ago
Read 2 more answers
Find the length of each side.
34kurt

Answer:

16.852

Step-by-step explanation:

All side lengths are the same in an octagon. What you do is take the diamater and multiply it by 0.383. Diamater is the radius doubled.

7 0
3 years ago
I got the first two can you help me with the last one PLZ
Nat2105 [25]

1. Geometric Sequence

2. a_n = a_{n-1} * 3

3. a_n = 6 * (3)^{n-1}

Step-by-step explanation:

Given sequence is:

6, 18, 54, 162,....

Here

a_1 =6\\a_2 = 18\\a_3 = 54

(a) Is this an arithmetic or geometric sequence?

We can see that the difference between the terms is not same so it cannot be an arithmetic sequence.

We have to check for common ratio (ratio between consecutive terms of a sequence) denoted by r

r = \frac{a_2}{a_1} = \frac{18}{6}= 3\\r = \frac{a_3}{a_2} = \frac{54}{18} = 3

As the common ratio is same, the given sequence is a geometric sequence.

(b) How can you find the next number in the sequence?

Recursive formulas are used to find the next number in sequence using previous term

Recursive formula for a geometric sequence is given by:

a_n = a_{n-1} * r

In case of given sequence,

a_n = a_{n-1} * 3

So to find the 5th term

a_5 = a_4*3\\a_5 = 162*3\\a_5 = 486

(c) Give the rule you would use to find the 20th week.

In order to find the pushups for 20th week, explicit formul for sequence will be used.

The general form of explicit formula is given by:

a_n = a_1 * r^{n-1}

Putting the values of a_1 and r

a_n = 6 * (3)^{n-1}

Hence,

1. Geometric Sequence

2. a_n = a_{n-1} * 3

3. a_n = 6 * (3)^{n-1}

Keywords: Geometric sequence, common ratio

Learn more about geometric sequence at:

  • brainly.com/question/10666510
  • brainly.com/question/10699220

#LearnwithBrainly

4 0
3 years ago
Please help me for this question
rosijanka [135]

The volume of the given trapezoidal prism is 312 cubic units.

Step-by-step explanation:

Step 1:

To find the volume of a trapezoidal prism, we multiply the area of the trapezoidal surface with the height of the prism.

The area of a trapezoidal surface, A = \frac{a+b}{2} (h).

a and b are the lengths of the upper and lower bases and h is the height of the trapezoid.

For the given trapezoid, a is 5 units long and b is 8 units long while height, h is 4 units.

The area of the trapezoidal surface, A =  \frac{5+8}{2} (4) = 6.5(4) = 26.

So the area of the trapezoidal surface is 26 square units.

Step 2:

To determine the volume of the prism, we multiply the area of the trapezoidal surface with the height of the prism.

The area is 26 square units and the height of the prism is 12 units.

The volume of the prism, V= 26(12) = 312.

The volume of the given trapezoidal prism is 312 cubic units.

7 0
3 years ago
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