F(x) = a(x-h)²<span> + k
</span><span><u>Given that the vertex is (-3 -6):</u>
</span>f(x) = a(x + 3)² -6
<span>
<u>Given that it passes through (0.0), find a:</u>
a(0 + 3)</span>² - 6 = 0
<span>
9a - 6 = 0
9a = 6
a = 6/9 =2/3
<u>So the equation is :</u>
</span>f(x) = 2/3(x + 3)² -6
<span>
<u>Write the equation in standard form:</u>
</span>f(x) = 2/3(x² + 6x + 9) - 6
f(x) = 2/3x² + 4x + 6 - 6
f(x) = 2/3x² + 4x
<span>
Answer: </span>f(x) = 2/3x² + 4x<span>
</span>
Answer:
37.68
Step-by-step explanation:
157x.24= 37.68
Hope its right.
Answer:
25 calculators
Step-by-step explanation:
each calculator costs $50 (1000÷20)
so 1250÷50=25
Answer:
Descarte's rule says that the polynomial will have the number of zeroes equal to the number of times the sign off the coefficient changes.
For positive real roots:

The coefficient of polynomial is:
+9 -4 +10
There is 2 time sign in changing in 1st and 2nd term and then in 2nd and 3rd term.
So,there will be 2 positive real roots or less but even.
For negative real roots find P(-x)


So, coefficient of above polynomial is:
-9 +4 -10
There is 2 time sign in changing in 1st and 2nd term and then in 2nd and 3rd term.
So,there will be 2 negative real roots or less but even.