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2 years ago

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Help me with this....After drawing a histogram....How do u find the class in which the median lies in a histogram....

1 answer:

Ann [662]2 years ago

5 0

Answer:

Get all the values of the histogram and put them in order:

For example 2,5,7,1,7,3 becomes 1,2,3,5,7,7 and then you get the middle number, which is in this case (3+5)/2=3.5

Then see which of the readings lie on 3.5.

Step-by-step explanation:

You might be interested in

Place the circles in order from the circle with the smallest area to the circle with the largest area

ladessa [460]

Where are the circles??

6 0

3 years ago

Read 2 more answers

When x =6 y=2 <br><br> What is:<br> 2(3x-6y)^2

ikadub [295]

Answer:

72

Step-by-step explanation:

We first substitute x = 6 and y = 2 into the equation

2(3 x (6) - 6 x (2)) ^ 2

First we multiply all the numbers in the bracket

2(18 - 12) ^ 2

Now we minus the numbers in the bracket

2(6)^2

Now we use the indice rule to do 6^2 which is 36

And then we multiply 36 by 2 which is 72

Hope it helps :)

3 0

2 years ago

Read 2 more answers

GIVING 100 POINTS FOR THESE 3 PROBLEMS

mart [117]

Answer:

Step-by-step explanation:

$A=\frac{a+b}{2}*h=\frac{4+7}{2}*3=16.5cm^2$

$A=\frac{ab}{2} =\frac{4*6}{2} =12in^2$

$A=wl=6*5=30in^2$

$12+30=42in^2$

$A=\frac{a+b}{2}h=\frac{28+40}{2}*30=1020ft^2$

Wall = A= $\frac{ab}{2} =\frac{6*30}{2}=90ft^2$

6 0

2 years ago

Read 2 more answers

Solve the triangle. Round your answers to the nearest tenth. Law of sines 6 A. M∠C=34 m ∠ C = 34 , b=25 b = 25 , c=16 c = 16 B.

PolarNik [594]

Answer:

$A = 43.0^o$

$B = 55.0^o$

$BC = 20.0$

Step-by-step explanation:

I will solve this question with the attached triangle

From the attachment, we have:

$\angle C =82^o$

$AB = 29$

$AC = 24$

Required

Solve the triangle

First, we calculate $\angle B$ using sine law:

$\frac{AC}{\sin(B)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{24}{\sin(B)} = \frac{29}{\sin(82^o)}$

$\frac{24}{\sin(B)} = \frac{29}{0.9903}$

Cross multiply

$\sin(B) * 29 = 24 * 0.9903$

$\sin(B) * 29 = 23.7672$

Divide both sides by 29

$\sin(B) = 0.8196$

Take arcsin of both sides

$B = \sin^{-1}(0.8196)$

$B = 55.0^o$

Next, calculate $\angle A$ using:

$A + B + C = 180^o$ --- angles in a triangle

$A + 55^o + 82^o = 180^o$

Collect like terms

$A = 180^o-55.0^o - 82^o$

$A = 43.0^o$

Next, calculate BC using sine laws

$\frac{BC}{\sin(A)} = \frac{AB}{\sin(C)}$

This gives:

$\frac{BC}{\sin(43.0)} = \frac{29}{\sin(82)}$

$\frac{BC}{0.6820} = \frac{29}{0.9903}$

Make BC the subject

$BC = \frac{29*0.6820}{0.9903}$

$BC = 20.0$

6 0

2 years ago

What are the coordinates of the image of Q for a dilation with center (0, 0) and scale factor 1/2?

Amanda [17]

The answer would be D. (2,2)
Since the scale factor is 1/2, all you have to do is multiply 1/2 by each of x-coordinate and y-coordinate of Q.
Multiplying by 1/2 is the same as dividing by 2, so you divide the x and y coordinates of Q to get the dilation image of Q as (2,2).

8 0

3 years ago