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kifflom [539]
3 years ago
7

Which equation, when graphed would appear narrower than the graph of y= 3x2 + 5

Mathematics
1 answer:
maria [59]3 years ago
4 0

Answer:

y = 4x^2 + 5 has the narrowest graph.

Step-by-step explanation:

The larger the coefficient of x^2 is, the narrower the graph will be.  Thus:

y = 4x^2 + 5 has the narrowest graph.

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Which test point holds true for y − 2x ≤ 1?
CaHeK987 [17]
So in order to find the correct answer, we can just easily plug in the values to check which ordered pair matches the given inequality above. So based on my solutions, the correct answer would be the last pair. 
<span> y − 2x ≤ 1
0 - 2(5)</span> ≤ 1
0-10  ≤ 1
-10  ≤ 1
Hope this answer helps.
3 0
3 years ago
1. Triangle JKL is dilated by a scale factor of 1.5 with
Oduvanchick [21]

Answer:

A. yes

B. yes

C. no

Step-by-step explanation:

The coordinates of each point are (x, y).

J (-2, -3)

K (0, 2)

L (1, -4)

After being scaled by 1.5 about the origin, the coordinates are (1.5x, 1.5y).

J (-3, -4.5)

K (0, 3)

L (1.5, -6)

7 0
3 years ago
Some smells are perceived as being more feminine or more masculine. Researchers asked a random sample of 300 American adults to
kiruha [24]

Question:

Some smells are perceived as being more feminine or more masculine. Researchers asked a random sample of 300 American adults to score quantitatively the perceived gender-orientation of lavender. Smaller scores indicate a more feminine scent and larger scores a more masculine scent. In this design, a gender-neutral scent would have a perceived gender-orientation score of 12. The participants gave the scent of lavender an average score of 10.28.

Is this evidence that the scent of lavender is not gender neutral, on average? Select the correct statement of H0, Ha, and the hypotheses parameter in the corresponding test. -

a) Let µ be the mean gender-orientation score for all smells being studied. We test H0: µ=12 versus Ha: µ≠12 ; The alternative is two-sided because we want to test if all of the smells are not gender-neutral.

b) Let µ be the mean gender-orientation score for lavender. We test H0:µ=1.28 versus Ha:µ≠10.28; The alternative is two-sided because we want to test if lavender is not gender-neutral.

c) Let µ be the mean gender-orientation score for lavender. We test H0: µ=12 versus Ha: µ≠12; The alternative is two-sided because we want to test if lavender is not gender-neutral.

d) Let µ be the mean gender-orientation score for lavender. We test H0: µ < 12 versus Ha: ≥ 12 ; The alternative is not two-sided because we want to test if lavender is gender-neutral.

Answer:

c) Let µ be the mean gender-orientation score for lavender. We test H0: µ=12 versus Ha: µ≠12; The alternative is two-sided because we want to test if lavender is not gender-neutral.

Step-by-step explanation:

Here, some smells are perceived to be more feminine while some are more masculine. The researcher picked a sample size of 300 american adults to score quantitatively the perceived gender-orientation of lavender.

We are told that when the score is smaller it indicates a mord feminine scent, when the score is larger it indicates a more masculine scent while a score of 12 indicates a gender neutral scent.

In this case the participants gave lavender a score of 10.28

From the above information we have the following :

Mean, µ = 12

Sample size = 300

Sample mean x' = 10.28

Since the sample mean is less than 12, the null and alternative hypotheses will be:

H0 : µ = 12

Ha : µ ≠ 12

This is a two tailed test because the alternative hypothesis is not gender based, which means lavender could be perceived to be either more feminine or more masculine.

The correct option is option C.

c) Let µ be the mean gender-orientation score for lavender. We test H0: µ=12 versus Ha: µ≠12; The alternative is two-sided because we want to test if lavender is not gender-neutral.

3 0
3 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
4 years ago
What is an equation of the line that passes through the point (-2,-8) and has the slope of 3
NeTakaya

Answer:

y = 3x - 2

Step-by-step explanation:

y +8 = 3 (x + 2)

y + 8 = 3x + 6

y = 3x - 2

3 0
3 years ago
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