Question

A3 -4a2+12-3a Factorise ?

Answer 1

STEP-BY-STEP SOLUTION:

= a^3 - 4a^2 + 12 - 3a

= a^2 ( a - 4 ) + 3 ( 4 - a )

= a^2 ( a - 4 ) - 3 ( a - 4 )

= ( a - 4 ) ( a^2 - 3 )

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Answer 2

$a^3-4a^2+12-3a=(a^3-4a^2)-(3a-12)\\\\=a^2(a-4)-3(a-4)=\boxed{(a-4)(a^2-3)}\\\\=(a-4)(a^2-(\sqrt3)^2)\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\boxed{(a-4)(a-\sqrt3)(a+\sqrt3)}$