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mylen [45]
3 years ago
13

A3 -4a2+12-3a Factorise ?

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0
STEP-BY-STEP SOLUTION:

= a^3 - 4a^2 + 12 - 3a

= a^2 ( a - 4 ) + 3 ( 4 - a )

= a^2 ( a - 4 ) - 3 ( a - 4 )

= ( a - 4 ) ( a^2 - 3 )

Please mark as brainliest if you found this helpful! : )
Thank you <3
Black_prince [1.1K]3 years ago
5 0

a^3-4a^2+12-3a=(a^3-4a^2)-(3a-12)\\\\=a^2(a-4)-3(a-4)=\boxed{(a-4)(a^2-3)}\\\\=(a-4)(a^2-(\sqrt3)^2)\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\boxed{(a-4)(a-\sqrt3)(a+\sqrt3)}

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Help please (will chose brainliest).
lara [203]
Answers with Explanation.


i. If we raise a number to an exponent of 1, we get the same number.

{10}^{1}  = 10

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

{10}^{2}  = 10 \times 10 = 100

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.



{10}^{3}  = 10 \times  {10}^{2}  = 10 \times 100 = 1000

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.


{10}^{4}  =  10 \times {10}^{3} = 10 \times 1000 =  10000

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.



{10}^{5}  = 10 \times  {10}^{4}  = 10 \times 10000 = 100000

{10}^{5}  = 100000

vi. Recall that,

{a}^{ - m}  =  \frac{1}{ {a}^{m} }
We apply this law of exponents to obtain,

{10}^{ - 2}  =  \frac{1}{{10}^{2} }  =  \frac{1}{100}

vii. We apply
{a}^{ - m}  =  \frac{1}{ {a}^{m} }
again to obtain,


{10}^{ - 3}  =  \frac{1}{ {10}^{3} }  =  \frac{1}{1000}





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3 years ago
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