Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:
m= 15 b=25
Step-by-step explanation:
the slope is 15 because thta is the unit rate and the missing point that isnt shown is (0,25)
To start, the first thing you need to know is that when you add decimals, you must line the decimal up, meaning, if you were adding 2.7+4.1, you have to make sure 2 is lined up with 4, and 7 is lined up with 1 so that the decimals align. Then, you add straight down from right to left and you get 6.8 as your answer.
Tamara travels 33,036 miles in a year
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hope this helps!
Answer:
b i believe the answer is
