Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
40:16, 16:40, 40/16, 16/40
Answer:
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
The ratio of boys and girls =3:5
Let
Number of boys=3x
Number of girls =5x
- According to the question Numbers of girls=130


- Now interchange both sides and get x




<h3>Now </h3>
The number of boys=3x
=3×26=78
Number of boys is 78.
Answer:
y=-3x+3
Step-by-step explanation:
your y in your points in the b in y=mx+b because it's the y intercept and then the slope is -3