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almond37 [142]
2 years ago
12

There are 82 chairs at a birthday party. The chairs need to be lined up in equal-sized rows. How many possible ways can the chai

rs be lined up?
Explain your answer using complete sentences.
Mathematics
1 answer:
natali 33 [55]2 years ago
5 0

Answer:

The number of possible ways can the chairs be lined up is 2 rows of 41.

Given that,

There are 82 chairs at a birthday party.

The chairs need to be lined up in equal-sized rows.

Based on the above information, the calculation is as follows:

= 2 \times 41=2×41

= 82 chairs

Here 2 denotes the rows.

Therefore we can conclude that the number of possible ways can the chairs be lined up is 2 rows of 41.

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Q1.

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Q2.

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L = 5y² - 2x → L = 5(2)² - 2(3) = 5(4) - 6 = 20 - 6 = 14

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D: 2y → 9 + (2)(2) = 9 + 4 = 13   NOT

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Q3.

3 + 6² = 3 + 36 = 39

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D: 2³ + 14 + 17 = 8 + 14 + 17 = 39    NOT

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