All categories

2 years ago

The length of a rectangle is four times its width.

Mathematics

2 answers:

quester [9]2 years ago

4 0

Answer:

y = mx + c

since m = 0

c = 9

Nastasia [14]2 years ago

4 0

Answer: 60

suppose: the width of a rectangle is x (x > 0)

⇒ The length of a rectangle is 4x

because the area of the rectangle is 144 ft

=> 4x.x = 144

⇔ x² = 144/4 = 36

⇒ x = 6

with x = 6 ⇒ The length of a rectangle is 4.6 = 24

the perimeter of the rectangle is (6 + 24).2 = 60

Step-by-step explanation:

You might be interested in

Please help ASAP-Nov 19 I need it for a test

lozanna [386]

First to Answer:

The slope is 0.1998. The number of calories is increased by 0.1998 for each 1 milligram increase in sodium.

I remember taking this test and getting this answer! Let me know if help with any of the other questions!

8 0

3 years ago

3x- 5=1 what does x represent

V125BC [204]

Answer:

x=2

Step-by-step explanation:

3x=5+1

3x=6

x=6/3

x=2

8 0

3 years ago

Read 2 more answers

Solve for x and y matrix

charle [14.2K]

Answer:

$x=-1$

$y=5$

Step-by-step explanation:

$\begin{pmatrix}x&y\\ \:-1&4\end{pmatrix}\begin{pmatrix}2&5\\ \:4&1\end{pmatrix}=\begin{pmatrix}18&0\\ \:14&-1\end{pmatrix}$

$\begin{pmatrix}x&y\\ -1&4\end{pmatrix}\begin{pmatrix}2&5\\ 4&1\end{pmatrix}$

$=\begin{pmatrix}x\times \:2+y\times \:4&5x+y\\ 14&-1\end{pmatrix}$

$=\begin{pmatrix}18&0\\ 14&-1\end{pmatrix}$

$\begin{bmatrix}x\times \:2+y\times \:4=18\\ 5x+y=0\end{bmatrix}$

$x=-1$

$y=5$

OAmalOHopeO

8 0

2 years ago

F(x) = 2(x+3)2 -7 a= h= k=

vlabodo [156]

Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

6 0

3 years ago

Ive been having this question for a while "what do you use first PEMDAS or Order of Operations". Well you might say it doesn't m

IgorLugansk [536]

Answer:

Order of Operations was aught at a younger age for those just grasping the idea of multiplication and division. Exposing PEMDAS at a young age would confuse them too much, hence the order of operation groups, addition/subtraction and multiplication/division. So for the second example problem, PEMDAS would be correct because it does involve you to use parentheses as well as exponents to solve for. Very easy to mix up between order of operations and PEMDAS, but just look at it as if Order of operations is a beginner level of PEMDAS.

Step-by-step explanation:

5 0

3 years ago