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Tema [17]
3 years ago
13

What shows the correct form of the quadratic function​

Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Answer:

The last one is the answer

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Aleka and Helene both opened savings accounts that earn 2.5% interest a year. Aleka puts $2,500 into her account. Helene put $1,
Xelga [282]

Given:

Amount in Aleka and Helene accounts represented by the following function:

Aleka: f(x) = 2500(1.025)^x

Helene: g(x) = 1500(1.025)^x + 200x

To find:

The function represents the difference, h(x) = f(x) -g(x), between the value of Aleka's and Helene's total savings after x years.

Solution:

We have,

f(x) = 2500(1.025)^x

g(x) = 1500(1.025)^x + 200x

Now,

h(x) = f(x)-g(x)

h(x) = 2500(1.025)^x-[1500(1.025)^x + 200x]

h(x) = 2500(1.025)^x-1500(1.025)^x - 200x

h(x) = 1000(1.025)^x - 200x

Therefore, the correct option is C.

8 0
3 years ago
Patricia’s dog, Max, weighs 6.75 kilograms. There are approximately 0.45 kilograms in 1 pound. Which measurement is closest to t
Pepsi [2]
15 pounds. 6.75/0.45= 15
6 0
3 years ago
Show that each system has no solution<br>y=x+1<br>-x+y=3
Phoenix [80]
Y=x+1
-x+y=3

-x+x+1=3
1=3

5 0
3 years ago
If a certain brand of icecream is 99% fat free, how many cups would you have to eat to ingest the same amount of fat that would
sdas [7]

Answer:

<em>10,000 cups </em>

Step-by-step explanation:

Direct proportional quantities are such that their quotients are always the same number. Example: If I need one cup of sugar to prepare 5 candies, I will need 2 cups of sugar to prepare 10 candies. The quotient 5/1 is equal to the quotient 10/2

Let's suppose a cup of regular ice cream would have 100 parts of fat.

The brand of ice cream mentioned in the question is 99% fat-free which means for every cup of their ice cream, we'll only get 1 part of fat. The relation is 100/1.

If we wanted 100 parts of fat out of fat-free ice cream we would need 100*100/1=10,000 cups of it

These numbers won't change if we used another number instead of 100 in the example shown.

6 0
3 years ago
HHHHHHEEEEEELLLLLLPPPPPPP!!!!!!!
Klio2033 [76]
Check the picture below

if that red segment, GJ, is parallel to the AE base segment of the triangle, then, the segment GJ is the midsegment of the triangle, and by the side-splitter theorem, those two triangles are similar.

7 0
3 years ago
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