Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
Step-by-step explanation:
8x+2y=16
2y=-8x+16
y=-4x+8
slope is -4
y-intercept is (0,8)
x-intercept is (2,0)
I can help!! But could you tell me what the equations are?
So assuming that youmeans there were 35 MORE rose plants than sunflower seeds, then
Rose:Sunflower =8:3
rose=sunflower+35
therefor
8 units=rose
3 units=sunflowers
rose-35=sunflower
8unit-35=3unit
5unit-35=0
5unit=35
therefor
35=5unit
divide by 5
7=1unit
so 8 units of roses
7 times 8=56
3 units of sunflowers
3 times 7=21
rose=56
sunflower=21
Mode 17,
Mean is 19.3
Median 18.