Put these number in order of size, smallest to largest:

In a 45-45-90 right triangle, what is the ratio of the length of one leg to the

balandron [24]

A 1:12 is the answer for this question

5 0

3 years ago

What's the scientific notation of 0.000028

Dmitry_Shevchenko [17]

2.8 x 10^-5 good luck

7 0

3 years ago

Read 2 more answers

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago

A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,

Alika [10]

The population of the moose after 12 years is 7692

Step-by-step explanation:

The form of the exponential growth function is $y=a(b)^{x}$ , where

a is the initial value
b is the growth factor

The table:

→ x : y

→ 0 : 40

→ 1 : 62

→ 2 : 96

→ 3 : 149

→ 4 : 231

To find the value of a , b in the equation use the data in the table

∵ At x = 0 , y = 40

- Substitute them in the form of the equation above

∵ $40=a(b)^{0}$

- Remember any number to the power of zero is 1 (except 0)

∴ 40 = a(1)

∴ a = 40

- Substitute the value of a in the equation

∴ $y=40(b)^{x}$

∵ At x = 1 , y = 62

- Substitute them in the form of the equation above

∵ $62=40(b)^{1}$

∴ 62 = 40 b

- Divide both sides by 40

∴ 1.55 ≅ b

∴ The growth factor is about 1.55

- Substitute its value in the equation

∴ The equation of the population is $y=40(1.55)^{x}$

To find the population of moose after 12 years substitute x by 12 in the equation

∵ $y=40(1.55)^{12}$

∴ y ≅ 7692

The population of the moose after 12 years is 7692

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

7 0

3 years ago

at the beginning of the school year Anderson Middle School had 480 students at the end of the year it had 504 students what is t

NikAS [45]

Answer:

The number of enrollments increased by 5%.

Step-by-step explanation:

Given that:

Number of students at the beginning of the year = 480

Number of students at the end of the year = 504

Change = 504 - 480 = 24

This indicates increase.

Percent of change = $\frac{Change}{Old\ number\ of\ students}*100$

Percent of change = $\frac{24}{480}*100$

Percent of change = 5%

Hence,

The number of enrollments increased by 5%.

4 0

2 years ago