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lana66690 [7]
3 years ago
7

Find the area of the triangle. Round your answer to the nearest tenth.

Mathematics
1 answer:
marin [14]3 years ago
6 0

Answer:

Fg is 6 and I have to

Step-by-step explanation:

The school timings for the next course will be a number of activities for students to participate in related to UAE culture and

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Write an equation for the nth term of the arithmetic sequence. -6,-9,-12,-15
poizon [28]

Answer:

a_{n} = - 3n - 3

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 6 and d = a₂ - a₁ = - 9 - (- 6) = - 9 + 6 = - 3 , then

a_{n} = - 6 - 3(n - 1) = - 6 - 3n + 3 = - 3n - 3

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3 years ago
Change to fraction 336%
noname [10]
84/25 (84/25 = 3.36)
Hope to help
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The _______ is the point where the x axis and y axis intersect <br> HURRY PLEASE
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Answer:

the answer is origin

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2. Create an estimated probability distribution for the time teens spend texting.
Furkat [3]

Answer:

<u><em>Hours</em></u>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<u><em>Frequency</em></u>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.

Hours          0     0.5    1.0   1.5  2.0   2.5  3.0  3.5  4.0  4.5  5.0

Frequency  170  82    220  153  92   58   40    15  12   18    10

Step-By-Step Explanation:

As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.

As given in the problem statement,

<em><u>Total Sample Size = 870</u></em>

To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:

Estimated Probability Distribution (Frequency*)=\frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}

<u><em>For Example:</em></u>

Estimated probability distribution that teens spend 0 hours texting=\frac{170}{870} =0.20

Similarly

Estimated probability distribution that teens spend 0.5 hours=\frac{82}{870} =0.09

Using the same formula we get:

<em><u>Hours</u></em>          0     0.5    1.0     1.5    2.0    2.5    3.0    3.5    4.0    4.5    5.0

<em><u>Frequency</u></em>* 0.2  0.09  0.25  0.18  0.11  0.07  0.05  0.02  0.01  0.02  0.01

(<em>Note: Frequency* is the estimated probability distribution)</em>

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3 years ago
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Represents a exponential form
lidiya [134]
5^4 that is how to represent an exponent 
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