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emmasim [6.3K]
3 years ago
12

How can you represent the solutions of an inequality

Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

, each and every value in the solution set will satisfy the inequality and no other value will satisfy the inequality. Example: Solve 2x + 3 ≤ 7, where x is a natural number.

natka813 [3]3 years ago
3 0
A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution.
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Draw a diagram that shows 1/5 times 30 equals 6
MrMuchimi

Total number = 30

1/5 of 30 = 1/5 x 30 = 6

The attached figures show the total number of filled circles in five lines. Each line have “6” filled circles.

So 5 lines having 6 filled circles = 5 x 6 = 30

<span>Every line represents “1/5” of total amount “30”. Which proved that 1/5 of 30 is equal to 6. </span>

3 0
3 years ago
Read 2 more answers
Write an equation for the graph, where y depends on x.
Over [174]

Answer:

y = -3x + 6

Step-by-step explanation:

Equation of straight line is given by,

y = mx + b

m = slope of the line

b = y-intercept

From the graph attached,

m = \frac{\text{Rise}}{\text{Run}}

   = \frac{-6}{2}

   = -3

y intercept 'b' = 6

Therefore, equation of the line will be,

y = -3x + 6

5 0
3 years ago
What is the slope of the line
zhuklara [117]
The slope of a line is the difference between the x-line and the y-line. Rise/run
6 0
3 years ago
On each coordinate plane, the parent function f(x) = |x| is represented by a dashed line and a translation is represented by a s
LuckyWell [14K]

Answer:

c

Step-by-step explanation:

it just is

8 0
3 years ago
A gear with a diameter of 12.0 inches makes 35 revolutions every three minutes. Find the linear and angular velocities of a poin
alina1380 [7]

Answer:

Angular velocity: \omega = \frac{7\pi}{18} \,\frac{rad}{s} (1.222\,\frac{rad}{s})

Linear velocity: v = \frac{14\pi}{3}\,\frac{m}{s} (14.661\,\frac{m}{s})

Step-by-step explanation:

The gear experiments a pure rotation with axis passing through its center, the angular (\omega), in radians per second, and linear velocities (v), in inches per second, of a point on the outer edge of the element are, respectively:

\omega = \frac{2\pi}{60}\cdot \dot n (1)

v = R\cdot \omega (2)

Where:

\dot n - Rotation rate, in revolutions per minute.

R - Radius of the gear, in inches.

If we know that \dot n = \frac{35}{3}\,\frac{rev}{min} and R = 12\,in, then the linear and angular velocities of the gear are, respectively:

\omega = \frac{2\pi}{60}\cdot \dot n

\omega = \frac{7\pi}{18} \,\frac{rad}{s} (1.222\,\frac{rad}{s})

v = R\cdot \omega

v = \frac{14\pi}{3}\,\frac{m}{s} (14.661\,\frac{m}{s})

7 0
3 years ago
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