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3 years ago

A supplementary angle that has a 41 degree angle what is X

Mathematics

1 answer:

KiRa [710]3 years ago

4 0

Answer:

X= 139

Step-by-step explanation:

1. Suplementary angle = 180 degrees

2. Set up the Equation

41 + x = 180

3. Solve

41 + x = 180

-41 -41

x = 139

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Anon25 [30]

Answer:

Step-by-step explanation:

One angle is greater than 90°: Obtuse triangle

Two sides are the same length: Isosceles triangle

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3 years ago

Simplifying fractions (picture provided)

stich3 [128]

Answer:

2 1/4

Step-by-step explanation:

- 5 1/4 - ( - 7 1/2)

Subtracting a negative is like adding

- 5 1/4 + 7 1/2

Get a common denominator of 4

-5 1/4 + 7 2/4

Subtract

7 2/4 - 5 1/4

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3 years ago

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What the answer now to the question

Lostsunrise [7]

Step-by-step explanation:

Hello!!!

Given, VXW is a Right angled triangle where WV =4 and XV =5.

now, by taking reference angle as angle W, and using tangent we get;

p=5

b=4

again, 

tan thita =p/b

tan thita = 5/4

so, tan thita =1.25.

now, to find angle W, we should do tan thita inverse;

or, (tan thita)-1= tan thita-1(1.25)

or, (tan thita) -1 =51.3401°.

Now, by rounding off we get,

tan thita (angle W )= 51°.

Hope it helps....

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3 years ago

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Svetradugi [14.3K]

Answer:

The weight of each circle is 2g

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3 years ago

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I need help for 2,3, and 4

emmainna [20.7K]

Answer:

x = -1 , y = 4

x = 7, y = -1

x = 1, y = 2

Step-by-step explanation:

2. 6x + 2y = 2, -3x - 4y = -13

3. 4x + 8y = 20, -4x + 2y = -30

4. y = -3x + 5, 5x - 4y = -3

We have to determine the solutions of this system of equations, basically look for x and y. First, let's solve through elimination.

6x + 2y = 2

-3x - 4y = -13

Multiply the second equation by 2 :

6x + 2y = 2

-6x - 8y = -26

Add the equations and solve for y :

-6y = -24

Divide both sides by -6 :

y = 4

Now that we have found y, we can substitute 4 in y of the first equation :

6x + 2(4) = 2

6x + 8 = 2

Subtract 8 from both sides :

6x = -6

Divide both sides by 6 :

x = -1

4x + 8y = 20

-4x + 2y = -30

We are asked to solve in elimination style, do as followed :

4x + 8y = 20

-4x + 2y = -30

Add and solve for y :

10y = -10

Divide 10 from both sides to get y alone :

y = -1

Now that we know y, we can substitute it into the first equation :

4x + 8(-1) = 20

4x - 8 = 20

Add 8 to both sides :

4x = 28

Divide 4 from both sides :

x = 7

y = -3x + 5

5x - 4y = -3

We are asked to solve with substitution :

Since the first equation has y alone, we can replace it with y in the second equation :

5x - 4(-3x + 5) = -3

Distribute :

5x + 12x - 20 = -3

Combine like terms :

17x - 20 = -3

Add 20 to both sides :

17x = 17

Divide 17 from both sides :

x = 1

Now that we know y, we can substitute x in the first equation with 1 :

y = -3(1) + 5

y = -3 + 5

y = 2

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3 years ago