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zlopas [31]
3 years ago
7

4/5, √9, -0.95, √32/8, 2.9, - √6 PLEASE order from least to greatest

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

-√6    -0.95    √32/8      4/5    2.9    √9

Step-by-step explanation:

4/5, √9, -0.95, √32/8, 2.9, - √6

4/5 = 0.8

√9 = 3

√32/8 = 4√2 / 8 = √2/2 = 0.707

-√6 = -2.449

-√6    -0.95    √32/8      4/5    2.9    √9

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Step-by-step explanation:

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The general equation for depreciation is given by y=a(1-r)^t where y=current value.
Jlenok [28]

With the help of the given equation, we know that the automobile is worth $12528.15 after four years.

<h3>What are equations?</h3>
  • A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
  • a formula that expresses the connection between two expressions on each side of a sign.
  • Typically, it has a single variable and an equal sign.
  • Like this: 2x - 4 Equals 2.
  • In the above example, the variable x exists.

So, the equation of depreciation: y = A(1 - r)∧t

The current value is y.

A is the initial cost.

r is the depreciation rate.

t is the time in years, and

In four years, we must ascertain the present value.

Now,

y = $24000(1 - 0.15)⁴

y = 24000(0.85)⁴

y = 24000 × 0.52200625

y = 12528.15

Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.

Know more about equations here:

brainly.com/question/28937794

#SPJ4

Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $

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1 year ago
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Answer:

10x - 2y

Step-by-step explanation:

<em>simplify</em><em> </em><em>the</em><em> </em><em>expression</em><em>.</em><em> </em>

<em>8x</em><em>–</em><em>2y</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>x</em><em> </em>

<em>combine</em><em> </em><em>numbers</em><em> </em><em>that</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>variables</em><em> </em>

<em>8x</em><em> </em><em>+</em><em> </em><em>x</em><em> </em><em>+</em><em> </em><em>x</em><em> </em>

<em>*</em><em>those</em><em> </em><em>x</em><em> </em><em>have</em><em> </em><em>1</em><em> </em><em>coefficient</em><em> </em><em>each</em><em>.</em><em> </em>

<em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>8x</em><em>+</em><em>1x</em><em>+</em><em>1x</em><em> </em><em>=</em><em> </em><em>10x</em><em> </em><em>then</em><em> </em><em>–</em><em>2y</em>

<em>10x</em><em>–</em><em>2y</em><em>.</em>

Hope it helps :)

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