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Shtirlitz [24]
3 years ago
13

On a multiple choice test with 100 questions and 5 answer per question, how many different ways can the test be completed? (b) O

n a multiple choice test with 10 equations and 5 answers per question, how many different ways can the test be completed if no two consecutive answers are ever the same?
Mathematics
1 answer:
NemiM [27]3 years ago
8 0

Answer and Step-by-step explanation:

(a)

Given that a multiple choice test consist of 100 questions such that there are 5 answers per question i.e., any of the 5 answers can be selected i.e., there are 5 ways of selecting an answer

Total no. of ways of completing the test =5^{100}  ways

(b)

In order to complete the test in a way that 2 consecutive answers should never be the same, question can be answered such that  only one of the 5 option is selected.

Therefore, answer to the first question can be given in 5 ways

to the next in 4 ways and for all other only 4 ways are there to answer the question for 10 equations.

So,

Total no. of ways to answer the given question =

5\times 4\times 4\times 4\times 4\times 4\times 4\times 4\times 4\times 4 = 1310720 ways

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The Range is the difference between the lowest and highest values. Example: In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9. So the range is 9 − 3 = 6.

Step-by-step explanation:

Hope this helps!

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In the diagram below, what is the ratio of unshaded parts to shaded parts?
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<u>1 shaded to 3 unshaded</u>

Step-by-step explanation:

Well,

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In a list of households, own homes and do not own homes. Four households are randomly selected from these households. Find the p
labwork [276]

Complete Question

In a list of 15 households, 9 own homes and 6 do not own homes. Four households

are randomly selected from these 15 households. Find the probability that the

number of households in the sample which own homes is   exactly 3

Answer:

Step-by-step explanation:

From the question we are told that

   The number of household is  n  =  15

    The number of household that own homes is  k  =  9

     The number of household that do not own homes is u = 6

      The number of households randomly selected is  q =  4

Generally the number of ways of selecting 3 household  from the total number of 9 households that own homes is mathematically represented as  

        A = ^{k} C_ 3

Here C stands for combination hence we would be making use of the combination feature in our calculator

 =>  A = ^{9} C_ 3

  =>  A =84

Generally the number of ways of selecting 1 household  from the total number of 6 households that do not own homes is mathematically represented as

    B  =  ^{u}C_1

=>  B  =  ^{6}C_1

=>  B  = 6

Generally the number of ways of selecting 4 household  from the total number of 15 households on the list  is mathematically represented as

    D = ^{n}C_4

=>  D = ^{15}C_4

=>  D = 1365

Generally the probability that the number of households in the sample which own homes is   exactly 3 is mathematically represented as

        P( X = 3) =  \frac{A * B}{D}

=>      P( X = 3) =  \frac{85 *  6}{1365}

X is here represent the number of household in the selected sample  that own homes

=>      P( X = 3) = 0.3736

7 0
3 years ago
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