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zhuklara [117]
2 years ago
14

Simplify the product using the distributive property. (a-7)(a-5)=?

Mathematics
2 answers:
Sever21 [200]2 years ago
5 0
The answer is a^2-12a +35
Anettt [7]2 years ago
4 0

Answer:

a^2-12a+35

Step-by-step explanation:

(a-7)(a-5)

a^2-7a-5a+35

a^2-12a+35

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Five less than four times a number is nine more than twice a number
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5-4a=9+2a
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At the movie theatre, child admission is $6.40 and adult admission is $9.70. On Monday, 155 tickets were sold for a total sales
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Less than or equal to 121 adult tickets.


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Which equals 121


Since we don't know how many children tickets were, sold it could be less than or equal to 121.
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How much material will Dmitri's mom need for the tent, including the floor?
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<h3>Answer:  21.4 square meters</h3>

Work Shown:

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Write 27% percent as a fraction in its simplist form
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A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic
Ket [755]

Answer:

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

Step-by-step explanation:

Data given and notation  

\bar X=5.25 represent the sample mean

s=3.98 represent the sample standard deviation

n=54 sample size  

\mu_o =4.73 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:  

Null hypothesis:\mu =4.73  

Alternative hypothesis:\mu \neq 4.73  

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

7 0
3 years ago
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