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Natasha2012 [34]
3 years ago
12

How many thirds are in7

Mathematics
1 answer:
Tanya [424]3 years ago
3 0
There are 21 thirds in 7.

21/3 = 7
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An algebraic expression that represents the product of r cubed and one hundred seven.
Nadya [2.5K]

Answer:

107r³

Step-by-step explanation:

4 0
3 years ago
Which angle determines whether or not quadrilateral SVUT is a trapezoid? What measure would the angle need to be for SVUT to be
Lorico [155]

Answer:  The answer is ∠TUV.

Step-by-step explanation: Given in the question a quadrilateral SVUT with ∠SVU = 112°. We need to determine the angle whose measure will decide whether or not the quadrilateral SVUT is a trapezoid.

We know that for a quadrilateral to be a trapezoid, we need only one condition that one pair of opposite sides must be parallel.

So, in quadrilateral SVUT, since the measure of  ∠SVU is given, so we can decide  it is a trapezoid or not if we know the measure of ∠TUV. As ST and UV cannot be parallel, so its meaningless to determine ∠TSV.

For SV and TU to be parallel to each other, we need

∠SVU + ∠TUV = 180° (sum of interior alternate angles).

Therefore,

∠TUV = 180° - 112° = 68°.

Thus, we need to determine ∠TUV and its measure shoul be 68°.

7 0
3 years ago
Assume that f(1000)=50 , and it's also true that the cost to the consumer of each item is $5, did the retailer make wise use of
andriy [413]
I would say that they didnt because if you plug anythin in that equation it wont be a solution......i think thats what it meant

4 0
3 years ago
Please answer Parts A, B, and C. I Will Mark Brainliest
bogdanovich [222]
A) John: 3.75+1.45m
Kiara: 6.25+0.55m

B) (3.75+1.45m)+(6.25+0.55m)
Added: 10+2m

C) (10+2m) divide by 2
Factored: 5+m
4 0
2 years ago
(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

4 0
2 years ago
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