The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
Answer:15
Step-by-step explanation:
1 2/3*9=15
Answer:
x - 8 ≤ 4
+8 +8 Add eight to both sides of the equation.
X≤12
2x + 3 > 9
-3 -3 Subtract three from both sides
2x>6 Divide both sides by 2
x>3
Hope this helps!
Have an amazing day/night!
At first glance, it seems like a good estimate; big numbers make bigger number.
But, this is multiplication, which means big numbers will make an extraordinarily big number, in proportion to the numbers themselves.
If you round 31 3/4 up to 32, you can multiply that by 50. To make the estimate easier, multiply 50 by 2,
50 x 2 = 100
Take the zeros off 50 and 30 to make this a bit simpler, and multiply 5 by 3,
5 x 3 = 15
Add each of the zeros you took off to the 15 to make 1500 (1 zero was taken off 50, and 1 off of 30),
And then add 1500 to that other 100
1500 + 100 = 1600
A good estimate for 50 x 31 3/4 would be 1600, not 800.
Therefore,
No. Brenda's estimate of 800 is NOT a good estimate.
Answer:
B
Step-by-step explanation:
Given
14 + 10y ≥ 3( y + 14) ← distribute
14 + 10y ≥ 3y + 42 ( subtract 3y from both sides )
14 + 7y ≥ 42 ( subtract 14 from both sides )
7y ≥ 28 ( divide both sides by 7 )
y ≥ 4 → B
