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Kruka [31]
3 years ago
5

What is an equation of the line that passes through the points (-7, -7) and (-7, 4)

Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

x=-7

Step-by-step explanation:

y=mx+c

m=rise over run

m=0

x=-7

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A pair of boots has an original price of $95. They are on sale for 35 percent off. What number can you multiply $95 by to equal
Dennis_Churaev [7]

Answer:0.35

Step-by-step explanation: this is same as 35 percent

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Choose the correct answer.
antiseptic1488 [7]

Answer:

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Step-by-step explanation:

I hope that the answer is clear

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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
9
iogann1982 [59]
Okay thanks for letting me know I love you love love bye
4 0
3 years ago
What is the quotient of 83.3 and 24.5
Svetradugi [14.3K]

Answer:

3.4

Step-by-step explanation:

83.3 divided by 24.5= 3.4

5 0
3 years ago
Read 2 more answers
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