3x(x+3)^2 is your answer
start 3x^3+18x^2+27x
Pull out common factor of 3x
3x(x^2+6x+9)
Factor into 2 (x+3)s
then <span>combine
</span>3x(x+3)^2
Your factors are 3x, (x+3) and (x+3)
Hope this helps. If it did, make it brainliest
Answer:
Step-by-step explanation:
20cd^-1
Answer:
Step-by-step explanation:
Let x represent the larger number.
Let y represent the smaller number.
x-y=4 Given
3x=5y-2 Given
Now we can just substitute; let x=4+y
Substitute 4+y for x in the second equation:
3(4+y)=5y-2
12+3y=5y-2
-2y=-14
y=7
Substitute back (into BOTH equations to double check work).
x, the larger number, is 11
