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GalinKa [24]
3 years ago
10

Explain how to solve 4^(x+3)=7 using the change of base formula log_by=log y/ log b. Round to the nearest thousandth

Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0

Answer:

x = -1.59

Step-by-step explanation:

We are here given a equation and we need to solve out for x. The given equation is ,

\sf\longrightarrow 4^{( x +3)}= 7

Take log to the base " e " on both sides , so that we can remove the variable from the exponent .

\sf\longrightarrow log_e 4^{x+3}= log_e 7

Simplify using the property of log , \sf log a^m = m log a , we have ,

\sf\longrightarrow (x + 3) ln 4 = ln 7

Distribute by opening the brackets ,

\sf\longrightarrow  x ln 4 + 3 ln 4 = ln 7

This can be written as ,

\sf\longrightarrow x ln 4 = ln 7 - 3ln4

Divide both sides by ln 4 ,

\sf\longrightarrow x = \dfrac{ ln7}{ln 4 } - \dfrac{ 3ln4}{ln4}

Simplify ,

\sf\longrightarrow x = \dfrac{ ln4 }{ln7 } -3

On simplifying , we will get ,

\sf\longrightarrow \boxed{\blue{\sf x = -1.59 }}

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