Answer:
a. it is arithmentic - this is because for each term there is a constant increase of 4, and the change between each term <u>doesn't change</u>
b. you need to find the nth term, by using the equation difference x n + 0th term: the difference is (+)4 and the 0th term is -9 (-5 is the 1st term, so to go one back we subtract 4 - the inverse operation), so the nth term is 4n -9. Now we do the inverse operation on 119 to see if it's a term (it is a term if it's an integer. So, first we do 119 <u>plus</u> 9 (inverse of - 9) to get 128, then divide it by 4 rather than multiplying. This gives us 32, and that tells us that 119 is the 32nd term of the sequence.
Answer:
<em>P=0.0000037</em>
<em>P=0.00037%</em>
Step-by-step explanation:
<u>Probability</u>
A standard deck of 52 playing cards has 4 aces.
The probability of getting one of those aces is
Now we got an ace, there are 3 more aces out of 51 cards.
The probability of getting one of those aces is
Now we have 2 aces out of 50 cards.
The probability of getting one of those aces is
Finally, the probability of getting the remaining ace out of the 49 cards is:
The probability of getting the four consecutive aces is the product of the above-calculated probabilities:
P=0.0000037
P=0.00037%
175/5= 35
The answer is 35 minutes.
Hope this helps!
We see that CF and DE are parallel to each other, which means that they had the same length with each other, so:
6n-1=5n+9
Subtract 5n for both side
6n-1-5n=5n+9-5n
n-1=9
Add 1 for both side
n-1+1=9+1
n=10
CF=
6n-1
=6(10)-1
=60-1
=59
DE=
5n+9
=5(10)+9
=50+9
=59
CD/FE:
4n+2
=4(10)+2
=42
True/False:
n=10 True
n=7 False
CF=59 True
FE=42 True
CD=30 False. As a result, n=10;CF=59; and FE=42 is your final answer. Hope it help!
