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storchak [24]
3 years ago
14

Which elements in the image are likely

Chemistry
1 answer:
Luda [366]3 years ago
4 0
D. There is not enough information to tell
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6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature
sineoko [7]

Answer: The final temperature of the water will be 34.0^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=6832 Joules

m= mass of water = 5.9mol\times 18g/mol=106.2g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 18.6^0C

Final temperature of the water = T_f  = ?

Putting in the values, we get:

6832=106.2\times 4.184\times (T_f-18.6)

T_f=34.0^0C

The final temperature of the water will be 34.0^0C

8 0
3 years ago
How many valence electrons does Rb (rubidium) have?
Murljashka [212]

Answer:

The total number of electrons in a valence shell is called valence electrons. The electron configuration of rubidium shows that the last shell of rubidium has an electron. Therefore, the valence electrons of rubidium(Rb) are one.

3 0
2 years ago
Potassium has nineteen protons. how many electrons does a neutral potassium atom have?
Flauer [41]
It has 19 electrons. I hope this helps.
8 0
3 years ago
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How many grams are in 5.17 moles of Bismuth ASAP
laiz [17]
1080.4285646 grams :)
4 0
3 years ago
Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%
Tomtit [17]

Answer:

m_{solute}=26.8g

Explanation:

Hello.

In this case, since the definition of by-mass percent is:

\%m/m=\frac{m_{solute}}{m_{solution}}*100\%

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}\\ \\m_{solute}=\frac{11.9\%*225g}{100\%}\\ \\m_{solute}=26.8g

Best regards.

6 0
4 years ago
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