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Vladimir [108]
4 years ago
12

What is the formula for the aqueous salt produced when hydroiodic acid is neutralized by potassium hydroxide?

Chemistry
1 answer:
coldgirl [10]4 years ago
5 0

Answer:

KOH(aq) + HCI(aq)  ----->  KCI(aq )+ H2O

base          acid               salt          water

hope this helps :)

Explanation:

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The following balanced equation shows the decomposition of water (H2O). According to the equation, how many oxygen atoms are in
coldgirl [10]
2 possibly 3 depends on if that of what looks like a zero is an O which it isn't so 2 but if it is 3.
3 0
3 years ago
Read 2 more answers
Give two examples of elevation.
jasenka [17]

Answer:

An example of elevation is a plane flying at 36,000 feet above the ground. An example of elevation is a pope being raised to the position of saint. An example of elevation is a ballet dancer leaping three feet in the air. ... At 8,850 m (29,028 ft), the summit of Mount Everest is the highest elevation on Earth.

5 0
3 years ago
Question 5 (1 point)
ollegr [7]

Answer:

0.00125 moles H₃X

Solution and Explanation:

In this question we are required to calculate the number of moles of triprotic acid neutralized in the titration.

Volume of NaOH used = final burette reading - initial burette reading

                                      = 39.18 ml - 3.19 ml

                                      = 35.99 ml or 0.03599 L

Step 1: Moles of NaOH used

Number of moles = Molarity × Volume

Molarity of NaOH = 0.1041 M

Moles of NaOH = 0.1041 M × 0.03599 L

                          = 0.00375 mole

Step 2: Balanced equation for the reaction between triprotic acid and NaOH

The balanced equation is;

H₃X(aq) + 3NaOH(aq) → Na₃X(aq) + 3H₂O(l)

Step 3: Moles of the triprotic acid (H₃X used

From the balanced equation;

1 mole of the triprotic acid reacts with 3 moles of NaOH

Therefore; the mole ratio of H₃X to NaOH is 1 : 3.

Therefore;

Moles of Triprotic acid = 0.00375 mole ÷ 3

                                     = 0.00125 moles

Hence, moles of triprotic acid neutralized during the titration is 0.00125 moles.

3 0
4 years ago
Can you please help me
Luba_88 [7]

Answer:................

Explanation:

4 0
3 years ago
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A metal weighing 7.101 g is placed in a graduated cylinder containing 33.0 mL of water. The water level rose to the 37.4 mL mark
musickatia [10]
Volume of the metal = change in volume reading
Volume = 37.4 - 33
Volume = 4.4 ml

Density = mass / volume
Density = 7.101 / 4.4
Density = 1.61 g/ml
7 0
3 years ago
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