Answer:
Density of the He atom = 12.69 g/cm³
Explanation:
From the information given:
Since 1 mole of an atom = 6.022x 10²³ atoms)
1 atom of He = ![1 \ atom \times (\dfrac{1 \ mole}{ 6.022 \times 10^{23} \ atoms}) \times ( \dfrac{4.003 \ grams}{ 1 \ mole})](https://tex.z-dn.net/?f=1%20%20%5C%20atom%20%5Ctimes%20%20%28%5Cdfrac%7B1%20%20%5C%20mole%7D%7B%20%206.022%20%5Ctimes%20%2010%5E%7B23%7D%20%20%5C%20atoms%7D%29%20%5Ctimes%20%28%20%5Cdfrac%7B4.003%20%5C%20grams%7D%7B%20%201%20%20%5C%20mole%7D%29)
![=6.647 \times 10^{-24} \ grams](https://tex.z-dn.net/?f=%3D6.647%20%5Ctimes%20%2010%5E%7B-24%7D%20%5C%20%20grams)
The volume can be determined as folows:
since the diameter of the He atom is approximately 0.10 nm
the radius of the He =
= 0.05 nm
Converting it into cm, we have:
![0.05 nm \times \dfrac{10^{-9} \ meters}{ 1 nm} \times \dfrac{ 1 cm }{10^{-2} \ meters}](https://tex.z-dn.net/?f=0.05%20nm%20%5Ctimes%20%20%5Cdfrac%7B10%5E%7B-9%7D%20%5C%20%20meters%7D%7B%201%20%20nm%7D%20%5Ctimes%20%5Cdfrac%7B%201%20cm%20%7D%7B10%5E%7B-2%7D%20%5C%20meters%7D)
![=5 \times 10^{-9} \ cm](https://tex.z-dn.net/?f=%3D5%20%5Ctimes%20%2010%5E%7B-9%7D%20%20%5C%20cm)
Assuming that it is a sphere, the volume of a sphere is
= ![\dfrac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
= ![\dfrac{4}{3}\pi \times (5\times 10^{-9})^3](https://tex.z-dn.net/?f=%5Cdfrac%7B4%7D%7B3%7D%5Cpi%20%20%5Ctimes%20%285%5Ctimes%2010%5E%7B-9%7D%29%5E3)
= ![5.236 \times 10^{-25} \ cm^3](https://tex.z-dn.net/?f=5.236%20%5Ctimes%2010%5E%7B-25%7D%20%5C%20cm%5E3)
Finally, the density can be calcuated by using the formula :
![Density = \dfrac{mass}{volume}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cdfrac%7Bmass%7D%7Bvolume%7D)
![D = \dfrac{6.647 \times 10^{-24} \ grams }{ 5.236 \times 10^{-25} \ cm^3}](https://tex.z-dn.net/?f=D%20%3D%20%20%5Cdfrac%7B6.647%20%5Ctimes%20%2010%5E%7B-24%7D%20%5C%20%20grams%20%7D%7B%205.236%20%5Ctimes%2010%5E%7B-25%7D%20%5C%20%20cm%5E3%7D)
D = 12.69 g/cm³
Density of the He atom = 12.69 g/cm³
Answer:
an electron in the outer energy level of an atom
Answer:
In the final solution, the concentration of sucrose is 0.126 M
Explanation:
Hi there!
The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:
Ci · Vi = Cf · Vf
Where:
Ci = concentration of the original solution
Vi = volume of the solution taken to prepare the more diluted solution.
Cf = concentration of the more diluted solution.
Vf = volume of the more diluted solution.
For the first dillution:
26.6 ml · 2.50 M = 50.0 ml · Cf
Cf = 26.6 ml · 2.50 M / 50.0 ml
Cf = 1.33 M
For the second dilution:
16.0 ml · 1.33 M = 45.0 ml · Cf
Cf = 16.0 ml · 1.33 M / 45.0 ml
Cf = 0.473 M
For the third dilution:
20.0 ml · 0.473 M = 75.0 ml · Cf
Cf = 20.0 ml · 0.473 M / 75.0 ml
Cf = 0.126 M
In the final solution, the concentration of sucrose is 0.126 M
Benzaldehyde or C6H5CHO would not undergo the aldol condensation because it does not contain an alpha-hydrogen in its structure. Aldol condensation is a type of reaction that happens between an enolate and an aldehyde or ketone leading to a alkene that has a planar structure. The lack of an alpha-hydrogen would not allow for it to undergo such process since it cannot enolize. Benzaldehyde undergoes a nucleophilic reaction known as Claisen-Schmidt condensation. It has somehow same mechanism of the aldol reaction however, the nucleophilic attack on the carbonyl happens even without the alpha-hydrogen but with an enolate that is from a ketone.