So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
C) Jayden divided 14 by 2 and then added 1.5.
Step-by-step explanation:
Jayden did
(14/2)+1.5 which is 8.5
so C is correct.
Hope this helps plz hit the crown :D
Answer:
C = 12.56m
Step-by-step explanation:
circumference is the distance around the outside of a circle. The r stands for radius, half way across, from the center(thats the little line on the diagram) "d" stands for diameter. That would be double the radius, bc its all the way across the circle through the center. The formula to find the CIRCUMFERENCE is given, C=pi × d
They told you to use 3.14 for pi. And also the radius is 2, so the diameter is 4
C = pi × d
C = 3.14 × 4
C = 12.56 meters
Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
