All categories

2 years ago

3 3/16 divided 3/8?

Mathematics

1 answer:

sdas [7]2 years ago

8 0

$\text {Hello! Let's solve this Problem!}$

$\text {When dividing a mixed number you have to convert it into an Improper Fraction}$

$\text {\underline {Multiply and Add}}$

$\text {3*16=48}$

$\text {48+3=51}$

$\text {The denominator stays the same. Therefore your Improper Fraction should be 56/16}$

$\text {\underline {The Next Step Is to Divide the Numerator and Denominator}}$

$\text {51/3=17}\\\text {16/8=2}$

$\text {\underline {The Final Step is to convert your Improper Faction (17/2) into a Mixed Number}}$

$\text {17/2=8.5}$

$\text {8.5 is the same as 8 1/2.}$

$\text {Note: To convert an Improper Fraction to a Mixed Number you divide the Numerator}$ $\text {and Denominator} }$

$\text {Best of Luck!}$

You might be interested in

The average of three test scores is 82. The scores on the first test and the third test are the same. The score on the second te

kondaur [170]

Answer:

Step-by-step explanation:

Let x = the test

(x + x + ( x - 6))/3=82

((3x - 6)/3) • 3= 82 • 3

3x - 6 + 6 = 246 + 6

3 3

x = 84

5 0

2 years ago

The answers ? Plssss I’ll mark u brianliest

frez [133]

Answer:

4. C

5. B

Step-by-step explanation:

4. Circumference = diameter * pi

pi is approximately 3.14

Diameter = 2*radius

Diameter = 2*8 = 16

Circumference = 3.14 (16), so the answer is C.

5. The question asking asking for the surface of the toy box.

Surface area of a cube = 6*the area of one face of the cube = 6 (edge * edge)

Substitute the edge with 2

Surface area of the toy box = 6(2*2) = 6(4) = 24

Surface area is 24 feet squared, so the answer is B

Hope this helps :)

Have an awesome day!!

4 0

2 years ago

Irene is N years old. If Tom is twice as old, which of the following algebraic statements shows h

aleksley [76]

Answer:

1. 2n

Step-by-step explanation:

5 0

2 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

2 years ago

Which value of x makes the equation below true? 7 + x = 84 A. 12 B. 77 C. 83 D. 91

garri49 [273]

Answer:

B. 77

Step-by-step explanation:

7 + x = 84

Subtract 7 from both sides

x = 77

8 0

1 year ago