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Blababa [14]
3 years ago
11

X squared+6x+5 what is this factorise

Mathematics
1 answer:
NISA [10]3 years ago
4 0
Well, your question is basically;
x²+6x+5
   Well first you have to find two numbers that when added will give you +6 and when multiplied will give you 5. Well, in this case, the numbers are; (+1 and +5). So you add them to the equation. So;
x²+1x+5x+5
  Hope you noticed that 6x was removed. Anyway;
   You have to put the equation in two brackets with two terms in each
(x²+1x)+(5x+5)
   Next, you bring out what is commom in each bracket and use it to divide what is in the bracket
x(x+1)+5(x+1)
   Now you notice that the two things in the bracket are the same. They have to be.
Next, you put the terms outside the bracket together and choose one of the terms in a bracket. So;
(x+5) (x+1)
     So the equation factorised is (x+5) (x+1). But if you want to go ahead to find x, then you can say;
(x+5)                             (x+1)
x+5=0                             x+1=0
Take the +5 over            Take the +1 over the equal to, where it becomes -1. So;
the equal sign where      x=-1
it becomes -5. So;
x=-5                        OR    x=-1
   By the way, here's a little secret, the answers are always the opposite of the two numbers chosen at the beginning(+1 and +5). Hope i helped. If you have any more problems, let me know.
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Calculate the volume of this prism<br> 20 cm<br> 30 cm<br> 10 cm
Ghella [55]

Answer:

6000(cm)^{3}

Step-by-step explanation:

30 \times 10 \times 20

300 \times 20

6000(cm)^{3}

<h3>Hope it is helpful...</h3>
5 0
3 years ago
Which is the interval notation represent the domain?
Kazeer [188]

Answer:

The first choice, (-\infty, 7) \cup (7, \infty).

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches 7, its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for x = 7. The point 7 should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of x = 7. Here's how to write that in interval notation:

  • The set of all real numbers can be expressed as the interval (-\infty, \infty). Note that infinity \infty (or (- \infty) itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
  • The set of all real numbers less than (not equal to) 7 is (-\infty,7 ) (both ends are excluded.) The set of all real numbers greater than (not equal to) 7 is (7, \infty).
  • The set of all real numbers that is not equal to 7 is the union of all real numbers less than 7 and all real numbers greater than 7. The union operator \cup connects two intervals.

In other words, the domain is (-\infty, 7) \cup (7, \infty).

5 0
3 years ago
Write the equation for the quadratic function in standard form
Ede4ka [16]

Answer:

y=x^2+6x+7

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

y = a(x-h)^2+k

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

y=a(x--3)^2+-2\\y=a(x+3)^2-2

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a

The vertex form of the equation is y=(x+3)^2-2.

To write in standard form, convert vertex form through the distributive property.

y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7

8 0
4 years ago
X completes one round of a running track in 8 minutes and Y completes it in 6
Oksanka [162]

Answer: It will be 24 mins

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A equation for (7,2) and (2,12)
alexira [117]

Well to find this line you want to know the slope and the y-intercept. So find the slope:

(y2-y1)/(x2-x1)

12-2 = 10

2-7 = -5

10/-5 = 2/-1

-2 is your slope

Now for y-intercept, find the point closest to the y-axis. That is the point (2,12), and if your slope is negative 2, that means that if you go up 4 and left 2, you should find the y-intercept:

12 + 4 = 16

16 is your y-intercept

So now lets write this out in an equation:

y = mx + b

m = slope

b = y-intercept

y = -2x + 16

there you go! hope this helps!

5 0
3 years ago
Read 2 more answers
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