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3 years ago

2. The angle measures of a triangle are shown in the diagram. What is the value of X

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

5 0

Answer: The angles inside a triangle are called interior angles. ... The three interior angles in a triangle will always add up to 180°. At each corner the exterior and interior angles are on a straight line, so at each corner these two angles add up to 180°.

Step-by-step explanation:

Sal proves that the angles of an equilateral triangle are all congruent (and therefore they all measure 60°), and conversely, that triangles with all congruent angles are equilateral.

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Find the angle between u = (8.- 3) and v = (-3,- 8) Round to the nearest tenth of a degree.

Nimfa-mama [501]

Answer:

Step-by-step explanation:

First you must calculate the module or the magnitude of both vectors

The module of u is:

$|u|=\sqrt{(8)^2 + (-3)^2} \\\\|u|=\sqrt{64 + 9}\\\\|u|=8.544$

The module of v is:

$|v|=\sqrt{(-3)^2 + (-8)^2} \\\\|u|=\sqrt{9 + 64}\\\\|u|=8.544$

Now we calculate the scalar product between both vectors

$u*v = 8*(-3) + (-3)*(-8)\\\\u*v = -24+ 24=0$

Finally we know that the scalar product of two vectors is equal to:

$u*v = |u||v|*cos(\theta)$

Where $\theta$ is the angle between the vectors u and v. Now we solve the equation for $\theta$

$0 = 8.544*8.544*cos(\theta)\\\\0 = cos(\theta)\\\\\theta= arcos(0)\\\\\theta=90\°$

the answer is 90°

Whenever the scalar product of two vectors is equals to zero it means that the angle between them is 90 °

5 0

3 years ago

Read 2 more answers

Simplify the expression

Studentka2010 [4]

The answer to your question is
x^33

7 0

3 years ago

A fly starts out 2 meters from a lightbulb, flies closer to the light, then farther away (2 meters again). At this point the fly

Lorico [155]

Answer

f(t)=2cos(t)

Step-by-step explanation:

let's describe the situation first, a fly is starting 2 meters from the bulb and flies towards the bulb and when it is really close to the bulb, it flies 2 meters further away from the bulb this means that it reaches d = 0m (distance from the bulb) and then flies further 2 meters so d = -2m.

it this point the fly returns back and touches the bulb and flies away (ends it's oscillatory motion ). d = 0 again and story ends here.

here if we want to model this problem with time function , the cosine function seems the best fit with amplitude of 2, so the answer is f(t) = 2cos(t).

Now you can ask why cosine function? well if you look at the graph or the plot of the function it perfectly captures the physical situation going on here in this problem.

Domain is 0 to 2 $\pi$ because it is one complete cycle and the range is -2 to +2.

6 0

3 years ago

I need the answer ASAP :( really struggling

pashok25 [27]

<h3>Answer: Choice A $-4 \le x \le -2$ </h3>

Explanation:

Ask yourself this: "When is the graph completely horizontally flat?" The answer to this question is when x is between -4 and -2. This is where the graph is constant. All other intervals are either increasing or decreasing.

Saying "The graph is constant" basically means "constant rate of change", which is another way of saying that the graph isn't changing. Constant means it stays the same.

So this is why the answer is $-4 \le x \le -2$

Note how only choice A has both endpoints in the negative region, so it is a quick way to spot the answer.

3 0

3 years ago

Here is your questions

viva [34]

Answer:

Step-by-step explanation:

strategy: find the distance of the two points, take half of that, b/c that will be the radius, Then use the area of a circle formula to find the answer

P1 = (1,-1) in the form (x1,y1)

P2= ((3,3) in the form (x2,y2)

dist = sqrt [ (x2-x1)^2 + (y2-y1)^2 ]

dist = sqrt [ 3 -1 )^2 + 3-(-1)^2 ]

dist = sqrt [ 2^2 + 4^2 ]

dist = sqrt [ 4 + 16 ]

dist = sqrt [20]

r = $\sqrt{20}$ /2

area of circle = $\pi$ $r^{2}$

area of circle = $\pi$ ( $\sqrt{20}$ /2)^2

area of circle = $\pi$ ( $\sqrt{20}$ /2)( $\sqrt{20}$ /2)

area of circle = $\pi$ (20 / 4)

area of circle = $\pi$ 5

area of circle = 5 $\pi$

3 0

2 years ago