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Svetach [21]
3 years ago
14

2. The angle measures of a triangle are shown in the diagram. What is the value of X

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
5 0

Answer: The angles inside a triangle are called interior angles. ... The three interior angles in a triangle will always add up to 180°. At each corner the exterior and interior angles are on a straight line, so at each corner these two angles add up to 180°.

Step-by-step explanation:

Sal proves that the angles of an equilateral triangle are all congruent (and therefore they all measure 60°), and conversely, that triangles with all congruent angles are equilateral.

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A ÷ 9 = 81 What must I do to both sides to solve for ¨a¨
stiks02 [169]

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a=729

Step-by-step explanation:

Solve for a by simplifying both sides of the equation, then isolating the variable.

8 0
3 years ago
Х2 + 2x, 3х + 5, x2 + 1, 6x - 4
professor190 [17]

Answess

Step-by-step explanation:

6 0
2 years ago
You buy a watch for 60$. Your friend buys the same watch a month later. It is now sold at a discount of 15%. What is the new sal
OleMash [197]

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Step-by-step explanation:

3 0
3 years ago
According to the Complex Conjugate Root Theorem, if a+bi is a root of a quadratic equation, then __blank__ is also a root of the
Trava [24]

Answer:

a-bi


Step-by-step explanation:

If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi

Because we have l, m and n are real numbers and they are the coefficients.

Sum of roots = a+bi + second root = -m/l

When -m/l is real because the ratio of two real numbers, left side also has to be real.

Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.

i.e. other root will be of the form c-bi for some real c.

Now product of roots = (a+bi)(c-bi) = n/l

Since right side is real, left side also must be real.

i.e.imaginary part =0

bi(a-c) =0

Or a =c

i.e. other root c-bi = a-bi

Hence proved.


3 0
3 years ago
A geologist examines 6 seawater samples for lead concentration. The mean lead concentration for the sample data is 0.903 cc/cubi
Gnesinka [82]

Answer:

Step-by-step explanation:

We want to determine a 95% confidence interval for the mean lead concentration of sea water samples

Number of samples. n = 6

Mean, u = 0.903 cc/cubic meter

Standard deviation, s = 0.0566

For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

0.903 +/- 1.96 × 0.0566/√6

= 0.903 +/- 1.96 × 0.0566/2.44948974278

= 0.903 +/- 0.045

The lower end of the confidence interval is 0.903 - 0.045 =0.858

The upper end of the confidence interval is 0.903 + 0.045 =0.948

Therefore, with 95% confidence interval, the mean lead concentration of the sea water is between 0.858 cc/cubic meter and 0.948 cc/cubic meter

7 0
3 years ago
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