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S_A_V [24]
2 years ago
9

Mark wants to buy 5 new video games from

Mathematics
1 answer:
vlada-n [284]2 years ago
4 0
He will have to pay about $82.34 at the checkout.
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Carey and Patrick both borrowed money from Melinda. Carey owes Melinda $25.00. Patrick owes Melinda 3/4 the amount that Carey ow
iragen [17]

Answer:

$18.75

Step-by-step explanation:

multiply 25 * 3/4 ( 0.75) and you get 18.75

4 0
2 years ago
Instructions: Match each equations with correct type of event.
Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

  • P(A)P(B|A) - Dependent event
  • P(A)+P(B) - Mutually exclusive events
  • P(A and B)/P(A) - Conditional events
  • P(A) . P(B) - Independent Events
  • P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}

Hence the correct match are -

  • \mathrm{P(A)P(B|A)\rightarrow} Dependent event
  • \mathrm{P(A)+P(B)}\rightarrow Mutually exclusive events
  • \mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow} Conditional events
  • \mathrm{P(A) . P(B)\rightarrow} Independent Events
  • \mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow} not Mutually exclusive events.

Learn more about Probability of Events here -

brainly.com/question/79654680

#SPJ10

5 0
1 year ago
Five times the sum of a number and 6 is 48
MissTica
5(n+6)=48

5n+30=48

5n=18

n=18/5
4 0
3 years ago
Ethan invested £500 in the bank for 2 years.
Anon25 [30]

Answer:

Step-by-step explanation:

I=PRT/100

40=(500XRX2)/100

R=(40X100)/500X2

R=4000/1000

R=4 percent/annum

3 0
3 years ago
From experience, an airline knows that only 80% of the passengers booked for a certain flight actually show up. If 9 passengers
Olenka [21]

Answer:  0.74

Step-by-step explanation:

Given : The probability that the passengers booked for a certain flight actually show up : p=0.80

The number of passengers are randomly selected : n= 9

Binomial probability formula to find the probability of getting success in x trial :-

P(x)=^nC_xp^x(1-p)^{n-x}

Then , the probability that more than 6 of them show up will be :-

P(x>6)=P(7)+P(8)+P(9)\\\\=^9C_7(0.8)^7(0.2)^{2}+^9C_8(0.8)^8(0.2)^{1}+^9C_9(0.8)^9(0.2)^{0}\\\\=\dfrac{9!}{7!(9-7)!}(0.8)^7(0.2)^{2}+(9)(0.8)^8(0.2)+(1)(0.8)^9\approx0.3020+0.3020+0.1342=0.7382\approx0.74

Hence, the probability that more than 6 of them show up = 0.74

7 0
3 years ago
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