c² = a² + b² - 2 a b cos C
2 a b cos C = a² + b² - c²
cos C = (a² + b² - c²) / 2ab
C = arccos( (a² + b² - c²) / 2ab )
C = arccos( (17² + 8² - 16²) / (2 (17)(8) ) )
C ≈ 69.11°
Answer: 69.1
Let see...
So we know that × is less than 14.3 subtract by 9.
We can figure out what × is is by subtracting 14.3 with 9 and then find the answer less than it.

So now we know that the answer can be 5.3 or more. This means that we can cross out 5.3, 6.4, and 7.5.
So it would be 3.1 and 4.2.
Answer:
What's the question?
Step-by-step explanation:
Answer:
B' (2, 5 )
Step-by-step explanation:
Under a counterclockwise rotation about the origin of 270°
a point (x, y ) → (y, - x ) , then
B(- 5, 2 ) → B' (2, 5 )
Answer:
![\displaystyle Yes \\ Range: Set-Builder\:Notation → [f(x)|-2 ≤ f(x) ≤ 4] \\ Interval\:Notation → [-2, 4] \\ \\ Domain: Set-Builder\:Notation → [x|0 ≤ x ≤ 7] \\ Interval\:Notation → [0, 7]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Yes%20%5C%5C%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bf%28x%29%7C-2%20%E2%89%A4%20f%28x%29%20%E2%89%A4%204%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%204%5D%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C0%20%E2%89%A4%20x%20%E2%89%A4%207%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B0%2C%207%5D)
Step-by-step explanation:
Just by looking at the graph vertically and horisontally, you can tell what the range and domain is, depending on whether the segments are <em>closed</em> or <em>opened</em>.
* This is a function because it passes the <em>vertical</em><em> </em><em>line test</em>.
** This is kind of like a sine wave.
I am joyous to assist you anytime.