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mezya [45]
3 years ago
7

What is the mass of 8.98 x 10^24 particles of CaCl2?

Chemistry
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

1656.12grams

Explanation:

To calculate the mass of a substance in a particle, we need to calculate the number of moles (n).

n = nA × 6.02 × 10^23

nA = 8.98 x 10^24 particles

number of moles = 8.98 x 10^24 ÷ 6.02 × 10^23

n = 8.98/6.02 × 10^ (24 - 23)

n = 1.492 × 10^1

n = 14.92moles of CaCl2

Molar Mass of CaCl2 where Ca = 40g/mol, Cl = 35.5g/mol

CaCl2 = 40 + 35.5(2)

= 40 + 71

= 111g/mol

Using mole = mass/molar mass

mass = molar mass × mole

mass = 111 × 14.92

mass = 1656.12grams.

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In a balanced chemical equation, the numbers of individual particles and the numbers of moles of particles are represented by th
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In a balanced chemical equation, the numbers of individual particles and the numbers of moles of particles are represented by the COEFFICIENTS.

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3 years ago
What is newtons 2nd law of motion
sergejj [24]

Answer: The second law of newton states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and also the mass of the object.

Explanation:

7 0
4 years ago
A molecule is known to have a molar absorptivity of 18,650 at a certain wavelength. A spectrometer is tuned to this wavelength a
iren2701 [21]

Answer:

17,932.69 g/mol is the molecular weight of the substance.

Explanation:

Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 1.04

c = concentration of solution =?

l = length of the cell = 1 cm

\epsilon = molar absorptivity of this solution = 18,650 M^{-1} cm^{-1}

Now put all the given values in the above formula, we get the molar absorptivity of this solution.

1.04=18,650 M^{-1} cm^{-1}\times c)\times (1cm)

c = 5.576\times 10^{-5} M

Concentration=\frac{\text{Mass of compound}}{\text{Molecular mass of compound}\times V}

V = Volume of the solution in L

Molecular weight of the substance = x

V = 100 mL = 0.1 L

Mass of the substance = 100 mg = 0.1 g

5.576\times 10^{-5} M=\frac{0.1 g}{x\times 0.1 L}

x = 17,932.69 g/mol

17,932.69 g/mol is the molecular weight of the substance.

6 0
3 years ago
For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.
Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0
3 years ago
What force must act on a 150 kg mass to give it an acceleration of 30 m/s squared? F=ma
Helga [31]

Answer:

its 120

Explanation:

i did it :)

4 0
3 years ago
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