Does washington england costa rica or south africa have warmest ocean surface water

A hydrogen atom requires a minimum energy of 2.18×10^-18 J atom to remove an electron from its ground state level. Determine whe

frosja888 [35]

Just find the energy of the <span>blueviolet light with a wavelength of 434.0 nm using the formula:

E = hc / lambda

E = energy
c= speed of light = 3 x 10^8 m/s
h = planck's constant = 6.6 x 10^{-34} m^2 kg / s
lambda = 434 nm = 434 x 10^{-9} m

Putting these values (with appropriate units) in the above formula :

we get: Energy, E = 4.5 x 10^{-19} J

E = 0.45 x 10^{-18} J

Now, the </span>minimum energy is 2.18×10^-{18} J but our energy is 0.45 x 10^{-18} J which is less.
<span>Means the electron will not be removed

</span>

5 0

3 years ago

3. How many moles are 1.707 x 10^24 atoms of carbon?

Paraphin [41]

Answer:

2.835 moles of carbon

Explanation:

By definition, there are 6.022x10^23 atoms (or compounds) in one mole.

Write and use this as a conversion factor:

(6.022x10^23 atoms)/mole

(1.707 x 10^24 atoms of carbon)/((6.022x10^23 atoms)/mole) = 2.835 moles carbon

8 0

2 years ago

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization

zzz [600]

Answer:

$\boxed{\text{889 g}}$

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

q = mL, where L is the latent heat of vaporization.

$\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}$

5 0

2 years ago

Calculate the change in enthalpy for the following reaction, using the bond enthalpy data provided below. (Note: you may round t

aliina [53]

Answer:

-514 kJ/mol

Explanation:

The bond enthalpy which is also known as bond energy can be defined as the amount of energy needed to split one mole of the stated bond. The change in enthalpy of a given reaction can be estimated by subtracting the sum of the bond energies of the reactants from the sum of the bond energies of the products.

For the given chemical reaction, the change in enthalpy of the reaction is:

Δ $H_{rxn} =$ [2(409) + 4(388) + 3(496) - 4(630) - 4(463)] kJ/mol = 818 + 1552 + 1488 - 2520 - 1852 = -514 kJ/mol

3 0

3 years ago

A gas at a pressure of 360 torrs and a volume of 750 ml. If the pressure becomes 1.5 atm what is the new volume?

r-ruslan [8.4K]

Answer:

V₂ = 236.84 mL

Explanation:

The relation between pressure and volume is inverse.

We can write it as follows :

$P_1V_1=P_2V_2$

We have,

P₁ = 360 torrs, V₁ = 750 mL, P₂ = 1.5 atm = 1140 torr.

So,

$V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{360\times 750}{1140}\\\\V_2=236.84\ mL$

So, the new volume of the gas is 236.84 mL.

4 0

3 years ago