Answer:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)
Explanation:
Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:
- an equilibrium constant is, first of all, a fraction;
- in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
- in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
- each concentration should be raised to the power of the coefficient in the balanced chemical equation;
- only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.
Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:
P: ?
V: 35,5L = 35,5 dm³
n: 0,54 mol
R: 83,14 hPa·dm³/mol·K
T: 223K
..................
pV = nRT
p = nRT/V
p = (0,54×83,14×223)/35,5
p = 282,02 hPa
Answer: 8.88g
Explanation:Please see attachment for explanation
Answer:
E = 16 J
Explanation:
We have,
You put scruffy can run up to 2 m/s on his fastest days scruffy has a mass of 8 kg
It is required to find the maximum kinetic energy on his fastest days. If v is the velocity, then kinetic energy is given by :
Plugging all the values,
So, the maximum kinetic energy on his fastest day is 16 J.
Answer:
67.3 atm
Explanation:
We'll begin by converting 25 ℃ to Kelvin temperature. This can be obtained as follow:
T(K) = T(℃) + 273
T(℃) = 25 ℃
T(K) = 25 + 273
T(K) = 298 K
Finally, we shall determine the pressure. This can be obtained by using the ideal gas equation as illustrated below:
Gas constant (R) = 0.821 atm.L/Kmol
Volume (V) = 212 L
Number of mole (n) = 584 moles
Temperature (T) = 298 K
Pressure (P) =?
PV = nRT
P × 212 = 584 × 0.0821 × 298
P × 212 = 14288.0272
Divide both side by 212
P = 14288.0272 / 212
P = 67.3 atm
Thus, the pressure is 67.3 atm
