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Veseljchak [2.6K]
3 years ago
14

En las competencias de atletismo hay 120 participantes; 30 en la prueba de 100 m, 50 en la de 200 m y 40 en la carrera de relevo

s; pero también hay 10 que participan en las 3 pruebas. ¿Cuál es la probabilidad de que un participante esté inscrito solamente en una prueba?
Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

120 by the questiom we have tl do plus or not

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Does the formula V = 4/3 pi r^3 represent a linear or nonlinear function? Explain.
Levart [38]
This is the volume of the sphere & is not at all a linear function.

A linear function of the form of y=kx (k is a given number/coefficient) where

y & x grow at the same rate. Then whatever the input (x) it will generate an output (y) always in the ration y/x, whereas v=4/3 πr³ (coefficient =k =4/3(π), if r increase by 2 units v will increase by 2³ =8 & for r = 3, v increase by 3³ =27.

In short v increases quicker than r. No it's not a linear function
6 0
3 years ago
Please help me im not smart
tester [92]

Answer:

i believe the answer will be 23

4 0
3 years ago
Read 2 more answers
Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6
Anettt [7]
Splitting up the interval [0, 6] into 6 subintervals means we have

[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]

and the respective midpoints are \dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2. We can write these sequentially as {x_i}^*=\dfrac{2i+1}2 where 0\le i\le5.

So the integral is approximately

\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2

Recall that

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6
\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2
\displaystyle\sum_{i=1}^n1=n

so our sum becomes

\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)
=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2

8 0
3 years ago
Write two equivalent ratios 3to5??
vesna_86 [32]

Answer:

3 : 5

6 : 10

9 : 15

12 : 20

15 : 25

7 0
3 years ago
Find the missing length
jasenka [17]

Answer: 15

Step-by-step explanation:

For this you will have to use pythagoras’ theorem.

The formula for the shorter side of this triangle is u²=c²-b² (or in this case u²=17²-8²).

17²=289

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The formula becomes u²=289-64 or u²=225

Then to find u on its own you have to square root 225.

The square root of 225 is 15.

3 0
3 years ago
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