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victus00 [196]
3 years ago
15

Can someone help me graph y=2(x+1)^2-5. Thanks!

Mathematics
1 answer:
german3 years ago
6 0

Answer:  

y= <u>41</u>

    8

Step-by-step

I Think I  am right I'm not rlly sure

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(Problem on image.)...
ANEK [815]
Hey there! :) 

In order to the find the missing side length of this triangle, we'll need to use the Pythagorean Theorem! 

That equation is : a² + b² = c²

a = adjacent side

b = long side of rectangle

c = hypotenuse

We're already given the values of both a & c, so let's plug everything in! 

a² + b² = c²  → a = 10 , b = ? , c = 20

(10²) + b² = (20²)

Simplify.

100 + b² = 400

Subtract 100 from both sides.

b² = 400 - 100

Simplify.

b² = 300

Get the square root of b² & 300.

\sqrt{b^2} =  \sqrt{300}

Simplify!

b = 17.3

So, the missing side length is the first answer choice : 17.3

~Hope I helped!~
7 0
3 years ago
Zack and his dad baked some cupcakes for his class. They put 6 cups on each of 8 plates. How many cupcakes did they put on the p
kolezko [41]

Answer:

48 cupcakes were put on the plates.

Step-by-step explanation: 6 x 8 = 48

I hoped this answer helped you solve your problem!

Sincerely, iloveyouplease123ims

8 0
3 years ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
Use the drop-down menus to complete the statements.
TiliK225 [7]

Answer:-23

Step-by-step explanation:

6 0
2 years ago
What is the least common multiple of 4 and 10?<br> 02<br> 0 4<br> 20<br> 40
viktelen [127]

Answer: 4 I think

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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