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morpeh [17]
3 years ago
12

What is the equation of the line that passes through point (4, 12) and has a y-intercept of —2?

Mathematics
2 answers:
zmey [24]3 years ago
5 0

Answer:

<h2>y = 3.5x - 2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

<h3>y = mx + b</h3>

m - slope

b - y-intercept

We have y-intercept b = -2. Substitute:

<h3>y = mx - 2</h3>

We have the point (4, 12) → x = 4, y = 12. Put them in the equation:

12 = 4m - 2         <em>add 2 to both sides</em>

14 = 4m       <em>divide both sides by 4</em>

14/4 = m → m = 3.5

Fofino [41]3 years ago
3 0

Answer:

y = 3.5x - 2

Step-by-step explanation:

We know that the y-intercept of our equation is -2, so our current equation is: y = mx - 2. Now we have to find m, which is the slope. Now, we plug in the points into the equation y = mx - 2, and we get 12 = 4m - 2. Thus, m is 3.5. Our final equation is y = 3.5x - 2.

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▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

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