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Answer:
(x, y, z) = (-1, 0, -3)
Step-by-step explanation:
We notice that the coefficients of z are such that elimination of the z term from the equations is made easy.
Adding equations 1 and 2:
(2x -3y -2z) +(x +3y +2z) = (4) +(-7)
3x = -3
x = -1
Adding equations 2 and 3:
(x +3y +2z) +(-4x -4y -2z) = (-7) +(10)
-3x -y = 3
Substituting for x, we get ...
(-3)(-1) -y = 3
0 = y . . . . . . . . . . . add y-3 to both sides
Then z can be found from any equation. Substituting for x and y in the second equation gives ...
-1 +2z = -7
2z = -6 . . . . . add 1
z = -3 . . . . . .divide by 2
The solution is (x, y, z) = (-1, 0, -3).
The answer should be B bc the point is at 1 and it rises 2 and runs 3 to the left so it’s negative
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Answer:
a. ∆EGF ≅ ∆EGD
Step-by-step explanation:
Congruent triangles would have the same side lengths and the same measure of angles.
From the figure given:
EG in ∆EGF ≅ EG in ∆EGD
GF in ∆EGF ≅ GD in ∆EGD, also
EF ≅ ED.
The three angles in ∆EFG are also congruent to the three angles in ∆EGD.
Therefore, ∆EGD is congruent to ∆EGF.
∆EGF ≅ ∆EGD
