Okay so this is your equation; 17=221/x
all you need to do is multiply 221 by 17 and you'll have your answer. I hope this helps!
solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
The inequality that can be used to represents all possible combinations of x, the number of hamburgers and y, the number of briskets that will be cooked is 5y + 0.25x ≤ 150
Given:
pounds of brisket = 5 lb
Pounds of hamburger = 0.25 lb
Total pounds of briskets and hamburgers = no more than 150 lb
number of hamburgers = x
number of briskets = y
No more than in inequality = (≤)
The inequality:
5y + 0.25x ≤ 150
Therefore, inequality that can be used to represents all possible combinations of x, the number of hamburgers and y, the number of briskets that will be cooked is 5y + 0.25x ≤ 150
Learn more about inequality:
brainly.com/question/18881247
Answer: 55.5 (A.)
Step-by-step explanation:
Since angle A = 29 and angle B = 41, angle C must be equal to 110
180 = m<A + m<B + m<C
180 = 29 +41 + m<C
180 = 70 + m<C
110 = m<C
Therefore, side c must be the longest, side b must be the second longest, and side a must be the shortest.
Since side length a, angle A, and angle B are known, one can use the law of sines to solve for side b.
Law of Sines: sinA/a = sinB/b = sinC/c
sinA/a = sinB/b
sin29/41 = sin41/b
b(sin29/41) = sin41
b = 41(sin41)/(sin29)
b = 55.48
b = 55.5
