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2 years ago

Pls help mark u brainlist

Mathematics

1 answer:

Molodets [167]2 years ago

8 0

Do what that person with the long explanation says it’s most likely right!!

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Wanda has three times more shirts than her brother, Will. The equation a = 3b, where a represents the number of shirts Wanda has

marusya05 [52]

Answer:

8 shirts

Step-by-step explanation:

Given the equation a = 3b, where

a = the number of shirts Wanda has

b = the number of shirts Wanda's brother (Will) has

Hence if Wanda has 24 shirts then

24 = 3b

Divide both sides by 3

24/3 = b

b = 8 shirts

Will has 8 shirts.

6 0

3 years ago

Read 2 more answers

a customers total bill is $50.50. The company charges a monthly fee of $28 plus 5 cents for each call. Use n to represent the nu

Doss [256]

.05n + $28 = $50.50

(.05n = $22.50)100

5n = 2250

n= 450 calls

7 0

3 years ago

Please help this is really hard for me I struggle on number lines please help

Katen [24]

Positive 18, going off the assumption that the tick 2 spaces away from -1 is positive 9.

8 0

3 years ago

Help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

Setler79 [48]

Answer:

diameter = 3,600 units

Step-by-step explanation:

Let $\pi$ = 3.14

C = 2 $\pi$ r

11,304 = 2(3.14)r

r = 1,800

d = 2r = 2(1,800) = 3,600

7 0

2 years ago

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

4 0

3 years ago