The correct answer for the question that is being presented above is this one: "C.) The graph of the function is positive on (–2, 4)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, then <span>C.) The graph of the function is positive on (–2, 4).</span>
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Vlad did not make a mistake.
Answer:
Step-by-step explanation:
coordinate of O(2,1),Y(3,-2),T(-3,-3)
let the reflected points are O',Y',T'
distance of O from y=2 is 1 unit.
∴ ordinate of O' =1+2(1)=3
or O' is (2,3)
distance of Y from y=2 is2+2=4
ordinate of Y'=-2+2(4)=6
so coordinate of Y' is (3,6)
distance of T from y=2 is (2+3)=5
so ordinate of T' =-3+2(5)=7
coordinate of T' is(-3,7)
The answer is -2 you use the formula -b over 2a