Solve for x. Round your answer to two decimal places. Show your work for full credit.
1 answer:
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We can apply some rules backwards
first
f'(x)=
(x-4)(-2x+4)
-2x^2+12x-16
we know that
so therefor maybe
-2x^2=rnx^{n-1}
2=n-1
n=3
rn=-2
3r=-2
r=-2/3
one is
second part
12x
12x=
x^1, 1=n-1
n=2
rn=12
2r=12
r=6
is the second bit
last part
-16
-16x^0=
0=n-1
n=1
rn=-16
1r=-16
r=-16
-16x^1
so therfor f(x)=
first
f'(x)=
(x-4)(-2x+4)
-2x^2+12x-16
we know that
so therefor maybe
-2x^2=rnx^{n-1}
2=n-1
n=3
rn=-2
3r=-2
r=-2/3
one is
second part
12x
12x=
x^1, 1=n-1
n=2
rn=12
2r=12
r=6
last part
-16
-16x^0=
0=n-1
n=1
rn=-16
1r=-16
r=-16
-16x^1
so therfor f(x)=
The most appropriate choice for similarity of triangles will be given by -
Speed of tip of the shadow of woman = 6 ft/s
What are similar triangles?
Two triangles are said to be similar, if the corrosponding angles of the triangles are same and the corrosponding sides of the triangles are in the same ratio.
Here,
The diagram has been attached here
Let the distance of woman from the pole be x ft and the distance of tip of the shadow to the pole be y ft.
Height of street light = 18 ft
Height of woman = 6ft
The two triangles are similar [As height of woman is parallel to the height of pole]
To find the speed, we have to differentiate both sides with respect to time 't'
Speed of tip of her shadow = 6 ft
To learn more about similarity of triangles, refer to the link-
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