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3 years ago

Solve for x. Round your answer to two decimal places. Show your work for full credit.

Mathematics

1 answer:

Leviafan [203]3 years ago

3 0

Answer:

sin(angle) = opposite/hypotenuse

Sin(39) = 9/ hypotenuse

hypotenuse = 9/sin(39) = 14.3011

x = 14.30

Step-by-step explanation:

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How many times would a face card (jack, queen, or king) likely be drawn from the deck in 260 draws?

Tanzania [10]

Answer:

8/10

Step-by-step explanation:

You would divide the cards and so you will get your answer

6 0

3 years ago

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Perform the operation. Enter your answer in scientific notation. 9 × 102 − 5.6 × 102 =

Arada [10]

Answer:

1489.2

Step-by-step explanation:

9*102-5.6*102=

102(9+5.6) =

102(9.0+5.6) =

102(14.6) =

102*14.6=

14.6*(100+2) =

(14.6*100+14.6*2) =

(1460+(14+.6) *2) =

1460+(28+1.2) =

1460+(28.0+1.2) =

1460+29.2=

1460.0+

29.2

=1489.2

3 0

3 years ago

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three cones have a volume of 192π cm³.Cone A has a radius of 2 cm. Cone B has a radius of 3 cm. Cone C has a radius of 4 cm. fin

andrew11 [14]

9514 1404 393

Answer:

A: 144 cm

B: 64 cm

C: 36 cm

Step-by-step explanation:

The volume of a cone is given by ...

V = (1/3)πr²h

Solving for h, we get ...

3V/(πr²) = h

Filling in the given values, we get ...

3(192π)/(πr²) = h

576/r² = h

Then the heights of the different cones are ...

A: r = 2, h = 576/4 = 144 . . . cm

B: r = 3, h = 576/9 = 64 . . . cm

C: r = 4, h = 576/16 = 36 . . . cm

8 0

3 years ago

If the diameter of the circle is above 20mm what is the area

Phoenix [80]

Answer:

The area would be 314.16 mm squared

7 0

3 years ago

Please math , help

Furkat [3]

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

$M = \frac{199+204+201+197+195+204+200}{7} = 200$

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

$S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18$

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

7 0

3 years ago