0.03x+0.06 (6500-x)=225
Solve for x
0.03x+390-0.06x=225
0.03x-0.06x=225-390
-0.03x=-165
X=165÷0.03
X=5500 invested at 3%
6500-5500=1000 invested at 6%
Actually,
I think the question should be, "In what range(s) of x-values must
there be a root of the POLYNOMIAL?"
Unless you are working with some real strange maths, polynomials are
smooth and continuous. If you drew a smooth and continuous line through
the points in the graph, where would the line have to cross the x-axis?
Answer:
14
Step-by-step explanation:
I think. sorry if i am wrong
The scale factor from A to B is 5/3 and the value of r is 33/5
<h3>The scale factor from A to B</h3>
From the figure, we have the following corresponding sides
A : B = 5 : 3
Express as fraction
B/A = 3/5
This means that, the scale factor from A to B is 5/3
<h3>The value of r</h3>
From the figure, we have the following corresponding sides
A : B = 11 : r
Express as fraction
B/A = r/11
Recall that:
B/A = 3/5
So, we have:
3/5 = r/11
Multiply by 11
r = 33/5
Hence, the value of r is 33/5
Read more about similar shapes at:
brainly.com/question/14285697
#SPJ1
Answer:
Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .
*angles in a quadrilateral is 360 degree
*2x+3x+5x+8x=360
*18x=360
*x=360/18
*x=20
now substitute x in these:
2x=2x20=40
3x=3x20=60
5x=5x20=100
8x=8x20= 160
so these are the following angles: 40,60,100 and 160
