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Nataly [62]
3 years ago
8

Prove that angles opposite to equal sides of an isosceles triangle are equal.

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

In ∆ABP and ∆ACP

AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

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