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3 years ago

4.85 + c > - 2.55=what

Mathematics

1 answer:

VikaD [51]3 years ago

4 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

4.85+c >-2.55 Equation/Question

Step 2

4.85 + c > - 2.55 Simplify

4.85 + c > - 2.55

Step 3

4.85 + c > - 2.55 add -4.85 to both sides

answer

c>-7.4

Hope this helps

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Martine’s town is building a volleyball court based on a scale drawing that is 40cm to 80cm and uses the scale 1cm:22.5cm write

never [62]

Answer:

$y=22.5x$

Step-by-step explanation:

we have that

The scale drawing is

$\frac{1}{22.5}\frac{cm}{cm}$

we know that

Using proportion find out the actual dimensions of the volleyball court

Let

x -----> drawing court lengths in cm

y ----> court lengths in cm

For x=40 cm

$\frac{1}{22.5}\frac{cm}{cm}=\frac{40}{y}\frac{cm}{cm}\\\\y=40*22.5\\\\y=900\ cm$

For x=80 cm

$\frac{1}{22.5}\frac{cm}{cm}=\frac{80}{y}\frac{cm}{cm}\\\\y=80*22.5\\\\y=1,800\ cm$

Find the equation for the proportional relation ship between drawing court lengths x in centimeters and court lengths in y centimeters

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

For x=40 cm, y=900

substitute

$k=y/x$ -----> $k=900/40=22.5$

The equation is

$y=22.5x$

5 0

3 years ago

ANSWER FASTTTT!!!

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

6 0

3 years ago

*In ∆ABC, on the extension of the side BC , draw a line segment CD ≅ CA . Draw the segment AD . The line segment CE is the angle

Leya [2.2K]

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Step-by-step explanation:

In ∆ABC

On the extension of the side BC , draw a line segment CD ≅ CA
Draw the segment AD
The line segment CE is the angle bisector of ∠ACB
The line segment CF is the median towards AD in ∆ ACD

We want to prove that CF ⊥ CE

Look to the attached figure

In Δ ABC

∵ CE is the bisector of angle ACB

∴ ∠ACE ≅ ∠BCE

In Δ ACD

∵ CA = CD

∴ Δ ACD is an isosceles triangle

∵ AD is the median towards AD

- In any isosceles triangle the median from a vertex to its opposite

side bisects this vertex

∴ AD bisects ∠ACD

∴ ∠ACF ≅ ∠DCF

∵ BCD is a straight segment

∵ CE , CA , CF are drawn from point C

∴ m∠BCE + m∠ACE + m∠ACF + m∠DCF = 180°

∵ m∠ACE ≅ m∠BCE

∵ m∠ACF ≅ m∠DCF

- Replace m∠BCE by m∠ACE and m∠DCF by m∠ACF

∴ m∠ACE + m∠ACE + m∠ACF + m∠ACF = 180°

∴ 2 m∠ACE + 2 m∠ACF = 180°

- Divide all terms by 2

∴ m∠ACE + m∠ACF = 90°

∴ EC ⊥ CF

CE ⊥ CF because m∠ECA + m∠FCA = 90°

Learn more:

You can learn more about perpendicular lines in brainly.com/question/11223427

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3 years ago

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4vir4ik [10]

Answer:

Step-by-step explanation:

Y= -6

X=-2

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3 years ago

Brad can bicycle at a rate of 55km/h. What is his speed in feet per second?

Brrunno [24]

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4 years ago