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kirza4 [7]
2 years ago
12

1. Match the polynomial with its end behavior.

Mathematics
1 answer:
zlopas [31]2 years ago
6 0

Using limit concepts, the matching pairs are:

A - 3

B - 1

C - 2

D - 4

The end behavior of a function f(x) is given by it's <u>limit as x goes to infinity.</u>

Function A:

f(x) = -2x + 3, then:

\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -2x = -2(-\infty) = \infty

\lim_{x \rightarrow \infty} f(x) \lim_{x \rightarrow -\infty} -2x = -2(\infty) = -\infty

Thus, inverse directions, so matching pair with 3.

Function B:

f(x) = x^2 - 6x + 3, then:

\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} x^2 = (-\infty)^2 = \infty

\lim_{x \rightarrow \infty} f(x) \lim_{x \rightarrow -\infty} x^2 = (\infty)^2 = \infty

Always positive, so matching pair with 1.

Function C:

f(x) = 1 - x^2 + 2x^3, then:

\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} 2x^3 = 2(-\infty)^3 = -\infty

\lim_{x \rightarrow \infty} f(x) \lim_{x \rightarrow -\infty} 2x^3 = 2(\infty)^3 = \infty

Same directions, thus, matching pair with 2.

Function D:

f(x) = 7 - x^4, then:

\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -x^4 = -(-\infty)^4 = -\infty

\lim_{x \rightarrow \infty} f(x) \lim_{x \rightarrow -\infty} -x^4 = -(\infty)^4 = -\infty

Always negative, so matching pair with 4.

A similar problem is given at brainly.com/question/9368215

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3 years ago
A fast food restaurant executive wishes to know how many fast food meals adults eat each week. They want to construct a 98% conf
adelina 88 [10]

Answer:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.1 represent the population standard deviation

n represent the sample size  

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.07 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formula to find it:"=-NORM.INV(0.01;0;1)", and we got z_{\alpha/2}=2.326, replacing into formula (b) we got:

n=(\frac{2.326(1.1)}{0.07})^2 =1336.006 \approx 1337

So the answer for this case would be n=1337 rounded up to the nearest integer

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Through (3, 4) and perpendicular to y = (1/3)x - 3
Oksana_A [137]

Answer:3

x

−

2

y

=

7

Explanation:

Write the standard form of the line that goes through  

(

3

,

1

)

and is perpendicular to  

y

=

−

2

3

x

+

4

.

The equation  

y

=

−

2

3

x

+

4

is in slope intercept form

y

=

m

x

+

b

where  

m

= slope and  

b

= the  

y

intercept.

The slope of this line is then  

m

=

−

2

3

A perpendicular slope is the opposite sign reciprocal. So, we change the sign of  

−

2

3

and switch the numerator and denominator.

Perpendicular slope  

m

=

3

2

To find the equation of the new line, use the point slope equation

y

−

y

1

=

m

(

x

−

x

1

)

where  

m

=

slope and  

(

x

1

,

y

1

)

is a point.

The slope is  

3

2

and the point is the given point  

(

3

,

1

)

.

y

−

1

=

3

2

(

x

−

3

)

a

a

a

Distribute

y

−

1

=

3

2

x

−

9

2

Standard form is  

a

x

+

b

y

=

c

where  

a

,

b

and

c

are integers and  

a

is positive.

a

a

2

(

y

−

1

=

3

2

x

−

9

2

)

a

a

a

Multiply the equation by  

2

a

a

a

a

a

2

y

−

2

=

3

x

−

9

−

3

x

a

a

a

a

a

a

a

−

3

x

a

a

a

Subtract  

3

x

from both sides

−

3

x

+

2

y

−

2

=

−

9

a

a

a

a

a

a

a

a

+

2

a

a

a

+

2

a

a

a  Add  2  to both sides  − 3 x + 2 y = − 7 − 1 ( − 3 x + 2 y = − 7 ) a a a Multiply the equation by  − 1 3 x − 2 y = 7

3 0
3 years ago
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