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2 years ago

50 points and brainliest for the best fastest answer

Mathematics

2 answers:

romanna [79]2 years ago

7 0

Answer:

Step-by-step explanation:

IgorLugansk [536]2 years ago

5 0

THis is an exam so NO

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If k(x) = 5x – 6, which expression is equivalent to (k + k)(4)?. . 5(4 + 4) – 6. 5(5(4) – 6) – 6. 54 – 6 + 54 – 6. 5(4) – 6 + 5(

Dmitrij [34]

K(x) = 5x-6
(k+k)(x) = k(x) + k(x) = 5x-6 +5x-6
just plug in x = 4,
(k+k)(4) = 5(4) -6 + 5(4) -6
thats your answer, the last option.

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2 years ago

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(21.) A writer earns $3400 a month. Last month she spent $204 on food.

Sergeu [11.5K]

6 percent was spent

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2 years ago

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A number cube is rolled and a coin is flipped.

KengaRu [80]

Answer:

Event 1: Rolling a number cube has 6 possible outcomes. Event 2: Flipping a coin has 2 possible outcomes. There are 12 possible outcomes.

3 0

2 years ago

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1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

2 years ago

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you take a group of 20 people going to the movies. kids’ tickets cost $4 each, and adults tickets $6 each. your total cost is $9

brilliants [131]

The number of kids in your group is 12.

Step-by-step explanation:

Given,

Number of people = 20

Cost of each kid ticket = $4

Cost of each adult ticket = $6

Total spent = $96

Let,

x be the number of kids ticket

y be the number of adult ticket

According to given statement;

x+y=20 Eqn 1

4x+6y=96 Eqn 2

Multiplying Eqn 1 by 4

$4(x+y=20)\\4x+4y=80\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(4x+6y)-(4x+4y)=96-80\\4x+6y-4x-4y=16\\2y=16$

Dividing both sides by 2

$\frac{2y}{2}=\frac{16}{2}\\y=8$

Putting y=8 in Eqn 1

$x+8=20\\x=20-8\\x=12$

The number of kids in your group is 12.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

2 years ago