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2 years ago

Cos^2x+cos^2x*cot^2x

Mathematics

1 answer:

prisoha [69]2 years ago

3 0

Answer:

Cos^2x csc^2x

Step-by-step explanation:

Cos^2x (1 + cot^2x)

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What is 2/9 in simplest form.

tatiyna

2/9 is in simplest form as 2 and 9 do not have any common factors.

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2 years ago

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Evaluate the surface integral. s (x + y + z) ds, s is the parallelogram with parametric equations x = u + v, y = u − v, z = 1 +

Stolb23 [73]

$S$ is given to be parameterized by

$\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\langle u+v,u-v,1+2u+v\rangle$

with $0\le u\le3$ and $0\le v\le2$ . We have

$\mathbf r_u=\langle1,1,2\rangle$
$\mathbf r_v=\langle1,-1,1\rangle$
$\mathbf r_u\times\mathbf r_v=\langle3,1,-2\rangle$
$\left\|\mathbf r_u\times\mathbf r_v\right\|=\sqrt{14}$

The surface integral is then

$\displaystyle\iint_S(x+y+z)\,\mathrm dS=\iint_S(x(u,v)+y(u,v)+z(u,v))\left\|\mathbf r_u\times\mathbf r_v\right\|\,\mathrm du\,\mathrm dv$
$=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}((u+v)+(u-v)+(1+2u+v))\,\mathrm dv\,\mathrm du$
$=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}(4u+v+1)\,\mathrm dv\,\mathrm du$
$=\displaystyle\sqrt{14}\left(8\int_{u=0}^{u=3}u\,\mathrm du+3\int_{v=0}^{v=2}v\,\mathrm dv+6\right)$
$=\displaystyle\sqrt{14}\left(8\int_{u=0}^{u=3}u\,\mathrm du+3\int_{v=0}^{v=2}v\,\mathrm dv+6\right)$
$=48\sqrt{14}$

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3 years ago

Solve for the value of x<br> A) 12<br> B) 42<br> C) -12<br> D) -42

pentagon [3]

The angles of a triangle will always add up to be 180 degrees total.

x + 82 + x + 82 + 40 = 180
2x + 164 + 40 = 180
2x + 204 = 180
Subtract 204 from both sides.
Think of it as “180 + (-204)”
2x = -24
Divide each side by 2.
x = -12

Answer: x = -12

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2 years ago

You placed a 11% down payment on a new home. Given that the amount of the down payment was $18,210.18, determine the price of th

Reil [10]

D its D gotta be 20 charecters

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3 years ago

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You are skateboarding at a pace of 30 meters every 5 seconds. your friend is in-line skating at a pace of 9 meters every 2 secon

AnnyKZ [126]

In order to graph the relationship, we will need to write the expression as the equation of a straight line as shown:

d = mt + b

d is the distance covered

t is the time taken

m is the speed

If you are skateboarding at a pace of 30 meters every 5 seconds. your friend is in-line skating at a pace of 9 meters every 2 seconds, this can be written as (5, 30) and (2, 9)

Get the slope of the line:

m = (9-30)/(2-5)

m = -21/-3

m = 7

Substitute m = 7 and the coordinate (2, 9) into the equation y = mt + b

9 = 7(2) + b

9 = 14 + b

b = -5

The required equation to plot will be expressed as y = 7t - 5

Plot the required graph

Learn more here: brainly.com/question/17003809

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2 years ago