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3 years ago

Let v be a vector with initial point (-5, -11) and terminal point (6,2). What is v?

Mathematics

2 answers:

White raven [17]3 years ago

4 0

Answer-The vector is

→

−

→

and the magnitude is

Explanation:

Let the point

(

−

)

and

(

−

)

Then,

−−→

(

−

(

−

)

−

)

(

−

)

The magnitude of

−−→

∣

−−→

∣

√

(

)

(

−

)

Step-by-step explanation:

dedylja [7]3 years ago

4 0

Answer:

It’s B

Step-by-step explanation:

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Complete the Square:<br> 5x^2+16x-40=8<br> (please show your steps)

Sav [38]

Answer:

Step-by-step explanation:

divide through by the coefficient of $x^{2}$

$\frac{5x^{2} }{5}$ + $\frac{16x}{5} + \frac{-40}{5} = \frac{8}{5}$

$x^{2} +\frac{16}{5}x -8 =\frac{8}{5}$

$x^{2} +\frac{16}{5} x = \frac{8}{5} +8$

$x^{2} + \frac{16}{5} x =\frac{48}{5}$

Add half of the square of the coefficient of x to both sides $(\frac{1}{2} X \frac{16}{5} ) ^{2}$

$x^{2} + \frac{16}{5}x + (\frac{1}{2} X \frac{16}{5} )^{2} =$ $\frac{48}{5} +(\frac{1}{2} X \frac{16}{5} )^{2}$

$x^{2} +\frac{16}{5} x +(\frac{16}{10}) ^{2} =\frac{48}{5} +\frac{64}{25}$

$(x +\frac{16}{10})^{2} =\frac{304}{25}$

$x +\frac{16}{10} =$ ± $\sqrt{\frac{304}{25} }$

$x = -\frac{16}{10}$ ± $\sqrt{\frac{304}{25} }$

$x=-\frac{16}{10} + \sqrt{\frac{304}{25} }$ or $-\frac{16}{10} - \sqrt{\frac{304}{25} }$

$x = 1.89$ or -5.09

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3 years ago

Find the y value for the point u that is located 1/5 the distance from point x to point x

Alexandra [31]

Answer: the point is 12/18

Step-by-step explanation:

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3 years ago

What is the equation of the line?

lina2011 [118]

y = x 2 − 3

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3 years ago

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What is the 20th term of 64,67,70,73,76

kozerog [31]

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Step-by-step explanation:

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3 years ago

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Suppose a NBA basketball player has 5% chance of picking up a foul every minute he plays. What is the probability that he will p

alukav5142 [94]

Answer:

He wont foul out with probability 0.9093

Step-by-step explanation:

The total number of fools he picked is a Binomial ditribution noted by X with parameters p = 0.05 and N = 48. The mean of this random variable is μ = np = 48*0.05 = 2.4 and the variance is σ² = np(1-p) = 2.4*0.95 = 2.28, hence its standard deviation is σ = √2.28 = 1.51.

Note that, if approximate probability is asked, we could just approximate X with a Normal random variable with mean 2.4 and standard deviation 1.51 (this can be done because of the central limit theorem). We will calculate the probability manually. He wont foul out if he picks 0,1,2,3 or 4 fouls, thus

$P(X \leq 4) = P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4) \\= 0.95^{48}+48*0.95^{47}*0.05+{48 \choose 2}*0.95^{46}*0.05^2+\\{48 \choose 3}*0.95^{45}*0.05^3+{48 \choose 4}*0.95^{44}*0.05^4 \\= 0.085+0.215+0.266+0.215+0.127 = 0.9093$

As a consecuence, he wont foul out with probability 0.9093.

8 0

4 years ago