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zaharov [31]
3 years ago
6

Determine whether each relation is a function if so provide the domain and range

Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

Answers:

  • Function? Yes
  • Domain = {1, 5, 10, 11, 14}
  • Range = {6, 50, 150, 176, 256}

=============================================

Explanation:

x = width

y = area

x is the input while y is the output.

We have a function because each input leads to exactly one output only. We don't have repeated x values.

The domain is the set of possible inputs. So we simply list the set of x values given in the table to get the domain to be {1,5,10,11,14}

The range is a similar story, but we list the possible y outputs getting {6,50,150,176,256}.

The curly braces indicate we have a set of values.

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we can see that the center is (-3, 3) and the radius is 9 units.

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The general circle equation, for a circle with a center (a, b) and radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we have the equation:

x^2 + y^2 + 6x = 6y + 63

Let's complete squares:

x^2 + y^2 + 6x - 6y =  63

(x^2 + 6x) + (y^2 - 6y) = 63

(x^2 + 2*3x) + (y^2 - 2*3y) = 63

Now we can add and subtract 9, (two times) so we get:

(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63

(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2

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If you want to learn more about circles:

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7 0
2 years ago
What is the result of gaining 10 pound then losing 20
kiruha [24]

Answer:

-10 pounds or 10 pounds loss

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3 0
3 years ago
Look at this graph:
andreev551 [17]

Answer:

The slope is 2/1.

Step-by-step explanation:

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8 0
3 years ago
Suppose the goal for mr. Luockwoods class had been 250 cans. Then 550 cans would have been what percent of the goal?
ser-zykov [4K]

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3 0
3 years ago
What is the area of a sector that has a radius of 25 mm and has an angle measure of 50
attashe74 [19]

Answer : The area of sector is, 272.57mm^2

Step-by-step explanation :

Formula used to calculate the area of sector in degree is:

Area of sector = \frac{\theta}{360}\pi r^2

where,

\theta = angle = 50^o

r = radius = 25 mm

Now put all the given values in the above formula, we get:

Area of sector = \frac{\theta}{360}\pi r^2

Area of sector = \frac{50}{360}\times 3.14\times (25)^2

Area of sector = 272.57mm^2

Therefore, the area of sector is, 272.57mm^2

7 0
3 years ago
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